Answer:
infinitely many answers, any odd integer n times π/2
ex. π/2, 3π/2, 5π/2
Step-by-step explanation:
we know that cos (π/2) or cos(3π/2) is 0
if one factor is 0, the product is zero, so we will not care about csc(x).
x is any odd integer n times π/2
Answer:
sin
/4 * sin
/6 = 1/2 *(cos
/12 - cos 5
/12)
Step-by-step explanation:
Formula:- sinX sinY = (1/2) [ cos (X - Y) - cos (X + Y) ]
sin(π/4)sin(π/6)
= (1/2)[cos(π/4 - π/6) - cos(π/4 + π/6)]
= (1/2)[cos(3π/12 - 2π/12) - cos(3π/12 + 2π/12)]
= (1/2)[cos(π/12) - cos(5π/12)]
Answer:
B :
Step-by-step explanation:
If you divide a rhombus using its diagonals, you get 4 right triangles, whose legs are both 1/2 the length of the diagonals.
This means that the legs of one of those 4 triangles have lengths of 2x/2, and 8x/2, so the legs of one of those triangles x and 4x. This makes the length of one side equal to
. Because all 4 sides are the same length, you multiply this value by 4, and get
, which is B.
<span>-8 < x -3 < 1
we have two inequations:
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
* x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun
Answer:
.125
Step-by-step explanation: