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1 year ago

Find the sum of 2.54 x 1019 and 3.218 x 1017. 3.2434 x 1036 2.57218 x 1036 3.2434 x 1019 2.57218 x 1019

Mathematics

1 answer:

GaryK [48]1 year ago

4 0

The sum of 2.54 x 1019 and 3.218 x 1017. 3.2434 x 1036 2.57218 x 1036 3.2434 x 1019 2.57218 x 1019 is 17811.9829.

As in the given problem we can see that multiplication of decimal number followed by summation is given so we an do it by parts.

The first part is 2.54*1019=2588.26

3.218 x 1017=3272.706

3.2434 x 1036= 3360.1624

2.57218 x 1036= 2664.77848

3.2434 x 1019=3305.0246

2.57218 x 1019=2621.05142

The sum is 17811.9829.

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Find the value of the variable What is x?

yaroslaw [1]

Answer:

x = 7

Step-by-step explanation:

I think there may be other ways to do this ... but this is one I guess....

one angle= 90 ( given)

the other = 45 (given)

the third = 90 + 45 + a = 180

(all angles of triangles is 180 [angle sum property])

a = 180 - 135

= 45

The base angles are equal so that means it is a isoscles triangle. In isoscles triangle, two sides are equal , so

if one side is 7

the x is 7 too

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3 years ago

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

VikaD [51]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(X = 8) = 0.0037$

$P(X < 5) = 0.805$

$P(X > 6) = 0.0206$

I would be surprised because the value is very small , less the 0.05

Step-by-step explanation:

From the question we are told that

The probability a randomly selected individual will not cover his or her mouth when sneezing is $p = 0.267$

Generally data collected from this study follows binomial distribution because the number of trials is finite , there are only two outcomes, (covering , and not covering mouth when sneezing ) , the trial are independent

Hence for a randomly selected variable X we have that

$X \ \ \~ \ \ { B ( p , n )}$

The probability distribution function for binomial distribution is

$P(X = x ) = ^nC_x * p^x * (1 -p) ^{n-x}$

Considering question a

Generally the the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing is mathematically represented as

$P(X = 8) = ^{12} C_8 * (0.267)^8 * (1- 0.267)^{12-8}$

Here C denotes combination

$P(X = 8) = 495 * 0.000025828 * 0.28867947$

$P(X = 8) = 0.0037$

Considering question b

Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when sneezing is mathematically represented as

$P(X < 5 ) =[P(X = 0 ) + \cdots + P(X = 4)]$

=> $P(X < 5 ) =[ ^{12} C_0 * (0.267)^0 * (1- 0.267)^{12-0} + \cdots + ^{12} C_4 * (0.267)^4 * (1- 0.267)^{12-4} ]$

=> $P(X < 5 ) = 0.02406 + 0.10516 + 0.21067 + 0.25580 + 0.20964$

=> $P(X < 5) = 0.805$

Considering question c

Generally the probability that fewer than half(6) covered their mouth when sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as

$P(X > 6) = 1 - p(X \le 6)$