We can think of the 10 black bags as 2 sets of 5-black bags (10 divided into groups of 5; 10 / 5 ; is 2 groups/sets). So, we would also have two sets of 3 (3 x 2 = 6), or 6 bags.

5 : 3 = 10 : 6

(multiply both numbers by 2)

4 0

2 years ago

WILL MARK BRAINLIEST !!!

iren2701 [21]

Answer:

(-3,3) Hope that this does help!

6 0

2 years ago

Which expression is equivalent to xy^2/9?

Law Incorporation [45]

Answer:

$xy^\frac{2}{9} = x*\sqrt[9]{y^2}$

Step-by-step explanation:

Given

$xy^\frac{2}{9}$

Required

The equivalent expression (see attachment)

We have:

$xy^\frac{2}{9}$

Split

$xy^\frac{2}{9} = x*y^\frac{2}{9}$

Apply the following laws of indices

$y^\frac{m}{n} = \sqrt[n]{y^m}$

So, we have:

$xy^\frac{2}{9} = x*\sqrt[9]{y^2}$

<em>Hence (d) is correct</em>

5 0

2 years ago

Help on 3. And 4. Thank you!

chubhunter [2.5K]

Answer:

#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.

#4.) Find how many minutes until the barrel is empty of water.

Let y = 0, to solve for time x.

0 = (-2/5)*x + 18

(2/5)*x = 18

x = (5/2)* 18 = 5*9 = 45 minutes

Up to and after 45 minutes, the barrel is empty of water.

Step-by-step explanation:

#2.)

minutes: 5, 10, 15, 20

water(gal): 16, 14, 12, 10

Find slope: slope m = (14 - 16)/(10 - 5) = -2/5

y - 10 = (-2/5)*(x - 20)

y - 10 = (-2/5)* x + 8

y = (-2/5)*x + 18

rate of change slope means that for every minute 2/5 gallons of water is lost

#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.

#4.) Find how many minutes until the barrel is empty of water.

Let y = 0, to solve for time x.

0 = (-2/5)*x + 18

(2/5)*x = 18

x = (5/2)* 18 = 5*9 = 45 minutes

4 0

3 years ago