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Alexandra [31]
3 years ago
9

What is the square root of pi

Mathematics
2 answers:
rosijanka [135]3 years ago
4 0
I believe it is 1.77245
Elena L [17]3 years ago
3 0
1.77245385
that is the answer
You might be interested in
Please HELP ASAP!
Elena L [17]

Answer:

C

Step-by-step explanation:

1,942+835

=2,784

then

2,784/12

=232

NOTE:

/ means divide

6 0
3 years ago
what is the completely factored form of xy3 – x3y? (the 3's are powers if it wasn't clear.)a. xy(y x)(y – x)b. xy(y – x)(y – x)c
VARVARA [1.3K]
I think the correct answer from the choices listed above is option A. The completely factored formed of the function xy^3 – (x^3)y would be xy (x+y) (x-y). It is factored as follows:

<span>xy^3 – x^3y
xy (y^2 - x^2)
xy (x+y) (x-y)
</span><span>
</span>
7 0
3 years ago
Read 2 more answers
What will be the value of the 22nd coefficient of a binomial raised to the power 25​
Alona [7]

Step-by-step answer:

We are looking at the coefficient of the 22nd term of (x+y)^25.

Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on,  22nd term is x^21y^4.

The twenty-second term of (x+y)^25 is given by the binomial theorem as

( 25!/(21!4!) ) x^21*y^4

=25*24*23*22/4! x^21y^4

= 12650 x^21 y^4

The coefficient required is therefore 12650, for a binomial with unit valued coefficients.

For other binomials, substitute the values for x and y and expand accordingly.

Question would have been more clearly stated if the actual binomial was given, as commented above.

4 0
3 years ago
Which expression is equivalent to -9a-10-6a+7−9a−10−6a+7
Gwar [14]

Answer:

−30a−6

Step-by-step explanation:

Let's simplify step-by-step.

−9a−10−6a+7−9a−10−6a+7

=−9a+−10+−6a+7+−9a+−10+−6a+7

Combine Like Terms:

=−9a+−10+−6a+7+−9a+−10+−6a+7

=(−9a+−6a+−9a+−6a)+(−10+7+−10+7)

=−30a+−6

BRAINLIEST. if you don't mind.

6 0
3 years ago
Which values are within the range of the piecewise-defined function?
musickatia [10]

Answer:  y < 1

<u>Step-by-step explanation:</u>

\begin{array}{c|c||l}\underline{x; x-3}&\underline{y=-x-2}&\\-3&-(-3)-2=1&\text{approaching but not including 1}\\-2&-(-2)-2=0&\\-1&-(-1)-2=-1&\end{array}

The first function has the range of y < -4

The second function has the range of y = -3

The third function has the range of y < 1

The largest y-value is 1 and the smallest y-value is -∞, therefore the range (y-values) are from -∞ to 1 → y < 1

6 0
3 years ago
Read 2 more answers
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