12a. The number of mole of Mg that contains 3.011×10²³ atoms is 0.5 mole
12b. The number of mole of 65 g of O₂ is 2.03 moles
13a. The mass of 0.25 mole of Pb is 51.75 g
13b. The mass of 2.4×10²⁴ atoms of C is 47.84 g
<h3>Avogadro's hypothesis </h3>
1 mole of substance = 6.02×10²³ atoms
<h3>12a. How to determine the mole of 3.011×10²³ atoms of Mg</h3>
6.02×10²³ atoms = 1 mole of Mg
Therefore,
3.011×10²³ atoms = (3.011×10²³ atoms × 1 mole) / 6.02×10²³ atoms
3.011×10²³ atoms = 0.5 mole of Mg
<h3>12b. How to determine the mole of 65 g of O₂</h3>
- Mass of O₂ = 65 g
- Molar mass of O₂ = 32 g/mol
- Mole of O₂ =?
mole = mass / molar mass
Mole of O₂ = 65 / 32
Mole of O₂ = 2.03 moles
<h3>13a. How to determine the mass of O.25 mole of Pb</h3>
- Mole of Pb = 0.25 mole
- Molar mass of Pb = 207 g/mol
- Mass of Pb =?
mole = mass / molar mass
Mass = mole × molar mass
Mass of Pb = 0.25 × 207
Mass of Pb = 51.75 g
<h3>13b. How to determine the mass of 2.4×10²⁴ atoms of C</h3>
6.02×10²³ atoms = 1 mole of C
But
1 mole of C = 12 g
Thus, we can say:
6.02×10²³ atoms = 12 g of c
Therefore,
2.4×10²⁴ atoms = (2.4×10²⁴ atoms × 12 g) / 6.02×10²³ atoms
2.4×10²⁴ atoms = 47.84 g of C
Learn more about Avogadro's number:
brainly.com/question/26141731
Learn more about mole:
brainly.com/question/13314627
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