1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksandr82 [10.1K]
3 years ago
11

How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.

Chemistry
1 answer:
Gekata [30.6K]3 years ago
8 0

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

No.of moles=mass in gram/molar mass

As for Fe mole =156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed= 2.797x3/2=4.1955

Mass of CO needed= 4.195mol x 28.01g/mol= 117.515g

You might be interested in
If an atom has 13 electrons how many electron shells does it have
svlad2 [7]

Answer:

Explanation:

If an atom has 13 electrons then it belongs to p-block of periodic table.

s level can accommodate 2 electrons.

p level can accommodate 6 electrons.

13 means 1s2 2s2 2p6 3s2 3p1.

As you can see there totally 5 sub-shells.

Total number of shells are 3(1,2,3).

4 0
2 years ago
How many grams of NaNO3 in 165 grams of H2O at 20°C would fully dissolve?
Fantom [35]

Answer: birchbox

Explanation:

6 0
2 years ago
how many grams of potassium chloride, KCL(molar mass is 74.55g/mol) are produced if 25 grams of potassium chlorate KClo^3 decomp
JulsSmile [24]

Answer:

                     Mass = 15.20 g of KCl

Explanation:

                    The balance chemical equation for the decomposition of KClO₃ is as follow;

                                            2 KClO₃ = 2 KCl + 3 O₂

Step 1: Calculate moles of KClO₃ as;

Moles = Mass / M/Mass

Moles = 25.0 g / 122.55 g/mol

Moles = 0.204 moles

Step 2: Find moles of KCl as;

According to equation,

                  2 moles of KClO₃ produces  =  2 moles of KCl

So,

               0.204 moles of KClO₃ will produce  =  X moles of KCl

Solving for X,

                       X = 2 mol × 0.204 mol / 2 mol

                       X = 0.204 mol of KCl

Step 3: Calculate mass of KCl as,

Mass = Moles × M.Mass

Mass = 0.204 mol × 74.55 g/mol

Mass = 15.20 g of KCl

6 0
3 years ago
_____ Ca(NO3)2 + _____ Fe → _____ Fe(NO3)3 + _____ Ca I need this done quick and fast Balancing chemical equations
cupoosta [38]

Answer:

3, 2, 2,3

..........................

8 0
3 years ago
HELP ME PLEASE!! If given a graduated cylinder, a beaker with alcohol and a scale, explain the steps to find the mass of 40 mL o
Luda [366]
<h3>Further explanation </h3>

In general, some people equate mass and weight.

Mass is one of the principal quantities, which is related to the matter , whereas weight is a force that leads to the center of the earth (Earth's gravitational force)

Steps that can be taken  to find the mass :

  • 1. Weigh graduated cylinder (empty)
  • 2. Pour the alcohol in the beaker into the graduated cylinder to the level of 40 ml
  • 3. Weigh again graduated cylinder + poured alcohol
  • 4. mass of alcohol 40 ml = mass in 3rd step - mass in the first step

6 0
3 years ago
Other questions:
  • Which 4 elements make up the bulk of living matter?
    10·1 answer
  • PLEASEE HELPP!
    10·1 answer
  • WILL MARK BRAINLIEST!
    9·1 answer
  • How many miles are in 1.50^22 atoms of silver?
    7·2 answers
  • In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t
    5·1 answer
  • Two elements that have properties similar to those of the element potassium(K). To those of krypton(Kr)
    6·1 answer
  • Help help help help help help​
    9·2 answers
  • Which object will experience the least amount of gravitational attraction toward Earth?
    13·1 answer
  • Why does D2O <br>have a higher boiling point than H2O ​
    12·2 answers
  • What is the chemical formula for the conjugate acid of the base trimethylamine (ch3)3n?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!