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2 years ago

Using the ob concepts and tools that best suit the situation is called a(n) ___________ to management.

1 answer:

8 0

Using the ob concepts and tools that best suit the situation is called a(n) contingency approach to management.

<h3>What is a contingency approach?</h3>

This approach to management is also known as the situational approach and holds that there is no single or textbook rule for the best way to manage an organization..

Most time, the contingency approach to management is based on the idea that there is no single best way to manage the resources.

Read more about contingency approach

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_______ is best described as the difference between the value a consumer attaches to a good or service and what he or she paid f

zysi [14]

Consumer Surplus

This is the difference between what consumers are willing and able to pay and what they actually do pay. You may be willing to spend up to $100 on a new pair of shoes but if you find the perfect pair on sale for $20 you will buy those and there will be an $80 surplus.

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3 years ago

Chamonix Chateau Rentals. You are planning a ski vacation to Mt. Blanc in Chamonix, France, one year from now. You are negotiati

nata0808 [166]

Answer:

The budgeted $ amount is $13,680.88

Explanation:

The purchasing power parity formula gives us an idea what an exchange spot rate would be in future period using the below formula:

Future spot rate=current spot rate*(1+US inflation)/(1+French inflation)

current spot rate=$1.3620

US inflation rate is 2.50%

French inflation is 3.50%

Future spot rate=$1.3620*(1+2.5%)/(1+3.5%)

future spot rate=$1.3488

The weekly cost of vacation would also be adjusted for inflation rate in France as follows:

Adjusted price=9800*(1+3.5%)=10143

Hence the cost of the one week rental would be 10143 multiplied by the future spot exchange rate of 1.3488 i.e $ 13,680.88 (10143*1.3488)

7 0

3 years ago

Ben White is the manager of a retail store. His work typically includes the routine, day-to-day interactions with customers and,

lubasha [3.4K]

Answer:

Explanation:

because he has to do a little of eveything

3 0

3 years ago

Angela Fox and Zooey Caulfield were food and nutrition majors at State University, as well as close friends and roommates. Upon

S_A_V [24]

Answer:

a) maximize 12x+16y subject to x+y≤60; x+2y≤80; 2x-3y≥0; x-9y≤0.

b) 40 fish and 20 beef dinners

c) $800

Explanation:

Let x and y represent the numbers of fish and beef dinners to prepare, respectively. Then the relations these values must satisfy are ...

x + y ≤ 60 . . . . . a maximum of 60 dinners will be sold

0.25x + 0.50y ≤ 20 . . . . . kitchen hours cannot exceed 20

x/y ≥ 3/2 . . . . . . at least 3 fish dinners for each 2 beef dinners will be sold

y ≥ 0.10(x +y) . . . . at least 10% of dinners sold will be beef

While satisfying these relations, we want to maximize the profit function:

p = 12x +16y

a) The linear programming problem can be formulated as ...

Maximize 12x +16y, subject to ...

x + y ≤ 60
x + 2y ≤ 80
2x - 3y ≥ 0
x - 9y ≤ 0

b) The graph shows the constraint inequalities with the comparison symbol reversed. The effect of that is to shade the area that is NOT part of the solution set, leaving the feasible region white. The vertex of the (white) feasible region that makes the profit line farthest from the origin is the solution we're looking for. Once the profit line is plotted so we can compare its slope to the lines bounding the feasible region, it becomes clear which vertex is the one that maximizes profit.

The solution is (x, y) = (40, 20).

40 fish dinners
20 beef dinners

c) The maximum earnings are estimated to be ...

($12)(40) +($16)(20) = $800

5 0

3 years ago

The Brisbane Manufacturing Company produces a single model of a CD player. Each player is sold for $182 with a resulting contrib

k0ka [10]

Answer:

Year 3 cashflow:

current system: 243,360

alternative system: 102,240

Present cost:

current system PV -$971,665.9146

alternative system PV -$1,075,964.17

Explanation:

Current Scenario:

42,000 inspection cost

Repairs:

1,520 identified x $75 = 114,000

Refunds:

480 units x $182 = 87,360

Total yearly cost: 243,360

PV of an annuity of $243,360 during 5 years:

Present Value of Annuity

$C \times \displaystyle \frac{1-(1+r)^{-time} }{rate} = PV\\$

C 243,360

time 5

rate 0.08

$243360 \times \displaystyle \frac{1-(1+0.08)^{-5} }{0.08} = PV\\$

PV $971,665.9146

New Scenario:

Inspection cost: $42,000 + $25,000 = $77,000

Repair cost: 350 units x $41 = $14,320

Refunds: 50 units x $182 x 120% = $10,920

Total yearly cost: $102,240

F0 cost:

470,000 workers trainings

210,000 purchase cost

Total F0 cost: 680,000

Present Value of Annuity

$C \times \displaystyle \frac{1-(1+r)^{-time} }{rate} = PV\\$

C 102,240

time 5

rate 0.08

$102240 \times \displaystyle \frac{1-(1+0.08)^{-5} }{0.08} = PV\\$

PV $408,214.6742

PV of residual value:

PRESENT VALUE OF LUMP SUM

$\frac{Maturity}{(1 + rate)^{time} } = PV$

Maturity 18,000.00

time 5.00

rate 0.08

$\frac{18000}{(1 + 0.08)^{5} } = PV$

PV 12,250.50

Net present value:

- 680,000 -408,214.67 + 12,250.50 = 1,075,964.17

4 0

2 years ago