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katrin [286]
2 years ago
5

Solve (8×5)÷4×5 step by step

Mathematics
2 answers:
Reika [66]2 years ago
7 0

Answer:

50

Step-by-step explanation:

Apply PEMDAS to this problem

8 × 5 = 40

Now you are left with: 40÷4×5

You then use PEMDAS from left to right from here

So 40 ÷ 4 would be 10, and now you are left with 10 × 5, which would be <u>50</u>.

jenyasd209 [6]2 years ago
4 0
Here you have to apply bodmas .
Firstly,you would have to to do bracket first, so it will be 8 times 5 which is equal to 40. After this you would divide by 4,so it will be 40 divided by 4 which is equal to 10, after applying this you would have to multiply 10 by 5 which is equal to 50.
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3 years ago
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Answer:

130 ft^2

Step-by-step explanation:

SA= surface area

SA= 2*l*w + 2*l*h + 2*w*h

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4 years ago
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Answer:

(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

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(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

P(t)=\frac{240t-40t^2}{t^2+20}

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

P(t)=\frac{240t-40t^2}{t^2+20} using quotient rule.

\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

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(c)Marginal Profit 11 Months after book release

P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

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3 years ago
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mafiozo [28]
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