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mafiozo [28]
3 years ago
5

How do you write 3 ones as a decimal

Mathematics
2 answers:
sergey [27]3 years ago
6 0
0.03 its 3 ones not 3 tenths
harina [27]3 years ago
4 0
3.0, because the 3 is in the ones place.
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Number Frequency 1,400 3 1,450 7 1,500 7 1,550 5 1,600 4 1,650 2 1,700 1 What is the mode?
poizon [28]
Mode is the number that shows up the most

in this case, it is 71,500 which shows up twice, one more than any of the other numbers

hope this helps
3 0
3 years ago
Read 2 more answers
Write the ratio 42 inches to 9 feet as a fraction in simplest form. Explain why you get the same result whether you convert feet
V125BC [204]
Let's convert one of these numbers:
1 foot = 12 inches

9 feet were 9*12=108 inches

so the ratio would be 42: 108

or we can simplify it: divide by 2:
21:54

divide by 3:
7:18

A ratio always stays the same no matter the unit or currency, so it doesn't matter which unit we convert it to.
4 0
3 years ago
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
Hello, attached is my problem. Please help!
weqwewe [10]

Answer:

15

Step-by-step explanation:

5 0
3 years ago
√20/125 answer in simpleset form<br>​
grigory [225]

Answer:

.4!

Step-by-step explanation:

first you divide 20 by 125 and get .16

then you take the square root of .16 and get .4

4 0
3 years ago
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