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Liono4ka [1.6K]

3 years ago

5

A triangle has a base of 15 feet and a height of 9 feet. What is the area of the triangle? Label the figure. Write the formula,

plug in the values, and solve.

1 answer:

bazaltina [42]3 years ago

8 0

Answer:

135...................

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Helpppp: Find the area of the parallelogram.

EleoNora [17]

Step-by-step explanation:

that is totally simple.

the area of a parallelogram is

baseline × height

basically the same as for a rectangle, just that in this more general form the height is no longer the other side.

in our case here

18×13 = 234 cm²

3 0

2 years ago

135 UB students were surveyed and asked how many hours a week they spent studying. The results are in the table below?

lesya692 [45]

Answer:

B) 11/27 ; c.) 5/27; D.) 17/27; E.) 3/13 ; F) 5/9

Step-by-step explanation:

- - - - - <5hrs - - (5 - 10hrs) - - (>10 hrs) - - Total

Male (M) 25 - - - - -- 25 - - - - - 20 - - - - 70

Female (F) 20 - - - - - - 30 - - - - - 15 - - - - 65

Total - - - 45 - - - - - - 55 - - - - - 35 - - - - 135

Probability = (required outcome / Total possible outcomes)

B) probability that a student studied(5 - 10 hours)

P(5 to 10 hours) = n(5 - 10 hours) / n(total) = 55/135 = 11/27

C) Find the probability that a student is a male and spends less than 5 hours studying

P(male and < 5 hours) = n(male ∩> 5 hours) / n(total) = 25/135 = 5/27

D) Find the probability that a student is a female or spends more than 10 hours studying.

P(female) + P(> 10hours) - P(Female ∩ > 10 hours) = 65/135 + 35/135 - 15/135 = 85/135 = 17/27

E.) Find the probability that a student spends more than 10 hours studying given that the student is a female?

n(Female ∩ > 10 hours) / n(Female)

15/65 = 3/13

F) Find the probability that a student is a male given that he spends less than 5 hours studying

n(male ∩ < 5hrs) / n(< 5 hours) = 25/ 45 = 5/9

5 0

3 years ago

Identify the steps to completing the square. Its on my algebra 2 homework and i have no idea what it means

Mrrafil [7]

1. your leading coefficient has to be 1 (nothing before the x^2). If there is you have to divide that out before you start.
2. Move your constant (the number without any x attached) to the other side of the equation
3. take 1/2 of the b term (the one with the x attached) and then square it and then add it to both sides
4. Factor the left side
5. Set each factor equal to 0 and solve

Here is an example:

4x^2-24x+20=0
The first term is not a 1 so we have to divide it out by 4 first
x^2-6x+5=0
Move the 5 to the other side. It becomes negative.
x^2-6x=-5
Take 1/2 of 6 (3) then square it (9) and add it to both sides.
x^2-6x+9=-5+9
Factor the left side
(x-3)(x-3)=4
(x-3)^2=4
To solve you need to square root both sides
x-3=+/-
x-3=+/-2
x=3+2=5
x=3-2=1
Those would be your two answers.

<span>Hope that helps</span>

4 0

2 years ago

Use the equation d=z–9 to find the value of d when z=10.<br><br> d=

denis23 [38]

Step-by-step explanation:

d = z - 9

d = 10 - 9 ----> substitute

d = 1

5 0

3 years ago

3 regions are defined in the figure find the volume generated by rotating the given region about the specific line

anastassius [24]

The volume generated by rotating the given region $R_{3}$ about OC is $\frac{4}{g} \pi$

<h3>Washer method</h3>

Because the given region ( $R_{3}$ ) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

$y=2(x)^{\frac{1}{4} }$

$x=(\frac{y}{2} )^{4}$

$y=2x$

$x=\frac{y}{2}$

$\int\limits^a_b {\pi } \, (R_{o^{2} } - R_{i^{2} } ) dy$

$R_{o} = x = \frac{y}{2}$

$R_{i} = x= (\frac{y}{2}) ^{4}$

$a=0, b=2$

$v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} ) dy$

$v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }} ] dy$

$v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]$

$v=\pi [\frac{1}{4} \frac{y^{3} }{3} \int\limits^2_0 - \frac{1}{2^{8} } \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi$

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0

2 years ago