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ludmilkaskok [199]
2 years ago
8

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics
1 answer:
Sergio [31]2 years ago
6 0

Answer:

6.7 units

Step-by-step explanation:

The distance between two points can be found using the formula below:

\boxed{{\text{Distance between 2 points}= \sqrt{(y_1 - y_2)^{2} + (x_1 - x_2)^{2}  } }}

Thus, distance between (-1, 2) and (2, -4)

=  \sqrt{( - 4 - 2)^{2} +  { [2-(-1) ]}^{2}  }

=  \sqrt{ {( - 6)}^{2}  +   {(2 + 1)}^{2} }

=  \sqrt{36 + 9}

=  \sqrt{45}

= 6.7 units (nearest tenth)

Additional:

For a similar question on distance between points, do check out the following!

  • brainly.com/question/23274198

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The diagram below shows the dimensions of a triangular park built in a new housing development. Two side lengths and one angle m
evablogger [386]
ANSWER

x = 50.5 \degree

EXPLANATION

We use the sine rule for solving triangles.

This is given by the formula,


\frac{ \sin(A) }{a}  =  \frac{ \sin(B) }{b}  = \frac{ \sin(C) }{c}


From the triangle,

\frac{ \sin(x) }{60}  =  \frac{ \sin(40) }{50}

We multiply both sides of the equation by 60 to get,

sin(x)  =  \frac{ 60\sin(40 \degree) }{50}


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We solve for x to obtain,

x = arcsin(0.7713)


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To the nearest tenth, we round to one decimal place to get,

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7 0
4 years ago
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

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Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

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3 years ago
If k(x) = 2x² -3.Vx, then k(9) is
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Answer:

159

Step-by-step explanation:

k (9) = (2 * 9^{2}) - 3

= (2 * 81) - 3

= 162 - 3

= 159

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