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3 years ago

12

Hey there, I really need help! I don't understand how to solve this. PLEASE HELP ME!!

1 answer:

Naily [24]3 years ago

7 0

Answer:

B

Step-by-step explanation:

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Round to the nearest tenth (TIMED PLEASE help!!!)

vredina [299]

Answer:

$A = 180 - (90 + 72) \\ A= 18° \\ \\ from \: pythogoras \\ a = 3.4 \\ b = 10.5$

4 0

3 years ago

A small country had a population of 2,254,000 people in the year 2012. If the population grows steadily

Anuta_ua [19.1K]

Step-by-step explanation:

year 2012 population = 2,254,000*3.5%

= 78.89

each year up to 2020

so 2020 - 2012 =8

78.89*8 = 631

total population at end of 2020 =2,254,000 + 631

= 2,254631

6 0

3 years ago

The latest poll from ESPN asked fans what their favorite sport was, considering pro, college and highschool levels. Out of 1000

shepuryov [24]

Answer:

Confidence interval is $0.2911$

Step-by-step explanation:

Given that 32% of fans sport is basketball as favorite sport. So total number of fans is,

$32\%\times 1000$

$= \dfrac{32}{100}\times 1000$

$=320$

So 320 fans favorite sport is basket ball.

Now find sample proportion ,

$\widehat{p}=\dfrac{number\:of\:people\:in\:the\:sample}{total\:number\:of\:people}$

Substituting the value,

$\widehat{p}=\dfrac{320}{1000}$

$\widehat{p}=0.320$

Formula for confidence interval is,

$CI=\widehat{p}\pm z\sqrt{\dfrac{\widehat{p}\left (1-\widehat{p}\right )}{n}}$

To calculate the z value.

$Confidence Level=1-\alpha$

$0.95=1-\alpha$

$0.05=\alpha$

Now divide above value by 2,

$\dfrac{0.05}{2}=\dfrac{\alpha}{2}$

$0.025=\dfrac{\alpha}{2}$

To find the value of z score calculate the area under the curve as follows

$A=\dfrac{1+CL}{2}$

$A=\dfrac{1+0.95}{2}$

$A=\dfrac{1.95}{2}$

$A=0.975$

On z table, find the value of 0.975. So the row corresponding to 0.975 is 1.9 and column corresponding to 0.975 is 0.06. Adding these two values the z score is 1.96.

or find the value from excel by using command as follows,

=NORM.S.INV(0.025)= -1.959963985

Now substituting the value,

$CI=0.320\pm 1.96\sqrt{\dfrac{0.320\left (1-0.320\right )}{1000}}$

$CI=0.320\pm 0.02891$

Lower end of the interval is,

$CI=0.320- 0.02891$

$CI=0.2911$

Upper end of the interval is,

$CI=0.320+ 0.02891$

$CI=0.3489$

Therefore 95% confidence interval is $0.2911$

7 0

3 years ago

Why do we need to find the average of something

daser333 [38]

Answer:

To know what is the average of it

Step-by-step explanation:

7 0

3 years ago

I need help with these five questions

garri49 [273]

Q1. ans b

Q2.ans d

Q3.ansc

Q4.ans b

Q5.ansa

4 0

3 years ago