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zavuch27 [327]
1 year ago
5

Please help me with this

Mathematics
1 answer:
kirill [66]1 year ago
3 0

Answer:

15/2 or 7.5

Step-by-step explanation:

5/6 (x + 1/2 + 4)

distribute 5/6 to each number

5/6x + 5/12 + 10/3

change the fraction 10/3 so that it will have the same denominator as 5/12

\frac{10}{3} *4 = 40/12

5/6x + 5/12 + 40/12\\5/6x + 45/12

divide both sides by 5/6

x = 9/2

5/6*9/2+5/12+10/3 = \frac{15}{2}

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Which number can be used as a common denominator for the fractions 1/4 and 5/6? Check all that apply.
Juli2301 [7.4K]
You could either use 12 or 24.
6 0
3 years ago
(1 point) Two six-sided dice are rolled (one red one and one green one). Some possibilities are (Red
anygoal [31]

Complete question:

Two six-sided dice are rolled (one red one and one green one). Some possibilities are (Red= 1, Green=5) or (Red=2, Green=2) etc.

a)How many total possibilities are there?

For the rest of the questions, we will assume that the dice are fair and that all the possibilities in (a) are equally likely.

b)What is the probability that the sum on the two dice comes out to be 11?

c)What is the probability that the sum on the two dice comes out to be 7?

d)What is the probability that the numbers on the two dice are equal?

Answer:

Kindly check explanation

Step-by-step explanation:

Total probabilities :

Total possible outcomes on each dice = 6

Total probabilities = 6² = 36

b)What is the probability that the sum on the two dice comes out to be 11?

Total required outcome = 2

Total possible outcomes = 36

Probability = required outcome / Total possible outcomes

P(sum on both dice = 11) = 2 / 36 = 1/18

c)What is the probability that the sum on the two dice comes out to be 7?

Required outcome = 6

Possible outcomes = 36

P(obtaining a sum of 7) = 6/36 = 1/6

d)What is the probability that the numbers on the two dice are equal

= required outcome / possible outcomes

Required outcome = 1,1 ; 2,2; 3,3; 4,4 ; 5,5 ; 6,6

= 6/36 = 1/6

4 0
3 years ago
The school that molly goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 6 sen
krek1111 [17]
The cost of a senior citizen ticket is $15 and the cost of a student ticket is $12.

How did I get this?
We know that 6 citizen tickets and 7 student stickers sold for $174 the first day. And 10 citizen tickets and 14 student tickets sold for $318 the second day.

1. create two equations out of this: C= citizen cost per ticket and S = student cost per ticket.

  6C + 7S = $174
10C + 14S = $318

2. Use process of elimination. Multiply the first equation by 2 because we want two variables to cancel out.

-12C - 14S = -$348
10C + 14S = $318
Combine like terms.

-2C = $30
Divide by -2 on both sides. The left side cancels out.

C = $30/-2
C = -$15 (In this case the negative doesn't matter)

C = $15 (cost of senior citizen ticket)

Plug the value of C into any of the two equations so we can get the value of S.

6($15) + 7S = $174
Distribute the 6 into the parenthesis.

$90 + 7S = $174
Subtract both sides by $90 and the left side will cancel out.

7S = $84
Divide both sides by 7.
S = $12

Student ticket: $12
Senior citizen ticket: $15




5 0
3 years ago
3/4-5/4m=113/24<br> please show work
bija089 [108]
May need to change into a mixed fraction

6 0
3 years ago
(F-32). Convert 12°C to
Kaylis [27]

Answer:

54

Step-by-step explanation:

multiply by 1.8 and add 32

12*1.8=21.6

21.6+32=53.6

53.6 rounded = 54

7 0
3 years ago
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