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ArbitrLikvidat [17]
3 years ago
7

Please help me out with this question

Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

0.31%

Step-by-step explanation:

Just look at the graph my man

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X−3y=1x+y=9
Brrunno [24]

I got this same question on a test, the answer is A.

7 0
3 years ago
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A toy store’s percent of markup is 30%. A model train costs the store $50. Find the markup.
Over [174]

Answer:  $15

Step-by-step explanation:

To find the markup price just multiply 30% by the amount.

30% * 50  

0.3 * 50 = 15

4 0
3 years ago
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If X and Y are independent continuous positive random
Leni [432]

a) Z=\frac XY has CDF

F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy

F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy

where the last equality follows from independence of X,Y. In terms of the distribution and density functions of X,Y, this is

F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy

Then the density is obtained by differentiating with respect to z,

f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy

b) Z=XY can be computed in the same way; it has CDF

F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy

F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy

Differentiating gives the associated PDF,

f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy

Assuming X\sim\mathrm{Exp}(\lambda_x) and Y\sim\mathrm{Exp}(\lambda_y), we have

f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy

\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}

and

f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy

\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0
3 years ago
IM ABOUT TO CRY IM SHAKING HELP
HACTEHA [7]

Answer:

  1. √11 is less than 3.5
  2. √5 is more than 2.1
  3. -5.3 is more than -5\frac{3}{5}  
  4. 8/10 is equal to 0.8

I hope this helps!

8 0
3 years ago
Need help is it correct or incorrect for all of them
gulaghasi [49]

Answer:A is correctly scientifically notated

B is incorrect

C is correctly notated

D is correct. 10 to the zero power simply means “1”

Step-by-step explanation:

7 0
3 years ago
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