1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AysviL [449]
3 years ago
14

Cherries are $3.99 a pound at the local market. If you buy 6 pounds and pay 8% tax, how much is the total for the cherries?

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

24.02 can i get brainliest

Step-by-step explanation:

You might be interested in
Solve each equation<br> (This is a fraction)<br> 6/11 = r/11
Mashutka [201]

Answer:

r=6

Step-by-step explanation:

6/11=r/11

cross product

11*r=6*11

11r=66

r=66/11

r=6

7 0
3 years ago
Figure JKLM is similar to figure PQRS.
Elis [28]

Answer:

the answer is D

Step-by-step explanation:

i found it in quizzes and Quizlet

4 0
3 years ago
2 4/5 ÷ 2 1/5 =<br> (Please answer as a fraction)
svet-max [94.6K]

Answer:

1 3/11

Step-by-step explanation:

8 0
3 years ago
Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}
algol [13]

Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

2cos(3x)= -\sqrt{2}

⇒ 2cos(3x)= -\sqrt{2}

⇒ \frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}

⇒ cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}

⇒ cos3x= \frac{-2}{2{\sqrt{2}}}

⇒ cos3x= \frac{-1}{{\sqrt{2}}}

⇒ cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})

⇒ 3x=\pm \frac{\pi}{4}

⇒ x=\pm \frac{\pi}{12}

Cosine General solution is :

x = \pm cos^{-1}(y)+ 2k\pi

⇒ x = \pm \frac{\pi}{12}+ 2k\pi , k is any integer .

At k=0,

⇒ x =\frac{\pi}{12} ,

At k=1,

⇒ x = - \frac{\pi}{12}+ 2\pi

⇒ x = \frac{23\pi}{12}

Therefore , Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

5 0
3 years ago
Mrs. Eaton's class is participating in the "Box Tops for Education" campaign. On the first day, her
storchak [24]
Each colection day: D
Number of tops collected on that day: N

D1=1; N1=2
D2=3; N2=8

1) Linear model
N-N1=m(D-D1)

m=(N2-N1)/(D2-D1)
m=(8-2)/(3-1)
m=(6)/(2)
m=3

N-N1=m(D-D1)
N-2=3(D-1)
N-2=3D-3
N-2+2=3D-3+2
N=3D-1

when D=6:
N=3(6)-1
N=18-1
N=17

<span>What is the number of tops collected on the sixth day based on the linear model?
</span>The number of tops collected on the sixth day based on the linear model is 17.

2) Exponential model
N=a(b)^D
D=D1=1→N=N1=2→2=a(b)^1→2=ab→ab=2   (1)

D=D2=3→N=N2=8→8=a(b)^3→8=a(b)^(1+2)
8=a(b)^1(b)^2→8=ab(b)^2   (2)

Replacing (1) in (2)
(2) 8=2(b)^2
Solving for b:
8/2=2(b)^2/2
4=(b)^2
sqrt(4)=sqrt( b)^2 )
2=b
b=2

Replacing b=2 in (1)
(1) ab=2
a(2)=2
Solving for a:
a(2)/2=2/2
a=1

Then, the exponential model is N=1(2)^D
N=(2)^D

When D=6:
N=(2)^6
N=64

<span>What is the number of tops collected on the sixth day based on the exponential model?
</span><span>The number of tops collected on the sixth day based on the exponential model is 64</span>
7 0
4 years ago
Other questions:
  • I need help I don’t understand
    14·1 answer
  • The question is in the image
    14·2 answers
  • Square root 2x+1 +3=0 is x=4 Do you agree? Explain why or why not
    6·2 answers
  • Can some1 help me what is the answer
    11·2 answers
  • Smallest possible integer for x &gt; -3
    5·1 answer
  • True or false<br> 12. The set of good students in our class is a well defined set
    7·1 answer
  • (I NEED THIS DONE ASAP PLEASE) Lena wants to plant a new lawn, but she knows that it’s not safe to run a mower on a hill with a
    13·1 answer
  • What is the greatest common factor of 24 and 40
    8·2 answers
  • John made a kite with all four sides the same length, as shown below. What is the perimeter of the kite?
    6·1 answer
  • Which graph correctly solves the system of equations below? y = x2 + 3x + 4 y = x2 + 2x + 1 (1 point) Select one: a. two quadrat
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!