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1 year ago

Answer number 3 please

Mathematics

1 answer:

Sever21 [200]1 year ago

8 0

M∩C = {8}

M∪C = {6, 8, 9 , 10}

Sets can be defined as an organized collection of objects represented in set-builder form or roster form.

Sets are mostly represented in curly braces {}

For example, A = {a, b, c, d, e} is a set.

From the information given, we have that:

M = {natural numbers larger than 7 but less than 11}
C = {multiples of 2 less than 12 but greater than 4}

Thus,

M = {8, 9, 10}

C = {6, 8, 10}

M∩C = Number common in both sets

M∩C = {8}

M∪C = Combinations of numbers in both sets without repetition

M∪C = {6, 8, 9 , 10}

Thus, the value of M∩C is 8 and that of M∪C is 6, 8, 9, 10

Learn more about sets here:

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The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

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Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

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Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

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substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

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substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

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Answer:

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