Explanation:
1.
Sodium, or Na, is 57.47% of the composition,
Hydrogen, or H, is 2.520% of the composition,
and Oxygen, or O, is 40.001% of the composition.
This is because mass% = mass/total mass x 100%.
2. For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 5.2 moles you are trying to make by the 6 moles of water you need, and you will need 31.2 moles.
3. x = 7.2 x 4 / 2 = 14.4 mol
Lithium is the first element of period 2 which reacts with fluorine to form LiF ( lithium fluoride ) . it is an inorganic compound . it is also a colorless solid . it is less soluble in water . it is chemically stable because of its comparable molecular mass .
Beryllium is the second element of period 2 which reacts with fluorine to give beryllium difluoride (BeF2) . it is inorganic compound . it is highly soluble in water. it is also a stable compound . it have low melting point .
Boron is the third element of period 2 which reacts with fluorine to form
BF3 (Boron trifluoride ) . it is a inorganic compound . it is colorless and toxic gas forms . it is stable in dry atmosphere but its octet is not satisfied .
Carbon is the 4th element of the period 2 which reacts with fluorine to form carbon tetrafluoride (CF4) . it is not soluble in water . it is a greenhouse gas . it dissolves in oil. it is very stable compound .it forms covalent bond .
Nitrogen is the 5th element of period 2 which reacts with fluorine to form nitrogen trifluoride (NF3) . it is also a inorganic compound . it is colorless and non-flammable . it is a stable gas at room temperature .
Oxygen is the 6th element of period 2 which reacts with fluorine to form oxygen difluoride (OF2) . it is colorless poisonous gas . it is partially stable or relatively stable .
Neon is a noble gas and also a stable element . it is odorless and colorless . so it is nonreactive . so it doesn't form bond with fluorine .
<h3>Learn more about Fluorine here :</h3>
brainly.com/question/3494441
#SPJ4
Ca(OH)₂: strong base
pOH = a . M
a = valence ( amount of OH⁻)
M = concentration
Ca(OH)₂ ⇒ Ca²⁺ + 2OH⁻ (2 valence)
so:
pOH = 2 x 0.005
pOH = 0.01
pH = 14 - 0.01 = 13.99
Answer:
0.33 ml
Explanation:
Formula for density: p = m/V (where p is <em>density</em>, m is <em>mass</em> and V is <em>volume</em>)
So, by applying the above formula:


The pressure inside the flask on heating it is given as 1.21 atm.
<u>Explanation:</u>
As per Guy Lussac's law, the pressure of any concealed volume of gas particles will be directly proportional to the temperature of the container of the gas particles.
So P ∝ T
To convert celsius to kelvin, add 273.15 to the temperature value in celsius
Since, here the initial temperature of the flask is given as 24°C, so in kelvin it will be 297.15 K. Similarly, the final temperature is said to be 104°C which will be equal to 377.15 K. Then the final pressure will be increased as there is increase in temperature. So, the final pressure inside the flask can be obtained as


So, the pressure inside the flask on heating it is given as 1.21 atm.