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2 years ago

What's the sequence of a single complete engine cycle?

Chemistry

2 answers:

alexdok [17]2 years ago

8 0

Answer:

Intake, compression, power, exhaust

Explanation:

To generate power, an engine must continually cycle through the same four stages of operation.

Intake: A mixture of air and fuel is drawn into the cylinder.

Compression: The piston rises and compresses the mixture.

Power: The spark plug ignites the mixture and causes an explosion.

Exhaust: The leftover gases are released from the cylinder.

erastovalidia [21]2 years ago

5 0

Answer:

Intake, compression, power, and exhaust

Explanation:

A four-stroke cycle engine is an internal combustion engine that utilizes four distinct piston strokes (intake, compression, power, and exhaust) to complete one operating cycle. The piston make two complete passes in the cylinder to complete one operating cycle.

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HEMP ME ITS DUE BY MIDNIGHT

balu736 [363]

Answer:

Explanation:

Option B is the correct answer

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1 year ago

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All of the Gathered in an investigation must be recorded. (Fill in the blank)

Zigmanuir [339]

The answer is "Incidents"

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2 years ago

The electrolysis of water forms H2 and O2. 2H2O Right arrow. 2H2 O2 What is the percent yield of O2 if 10.2 g of O2 is produced

Mama L [17]

Answer:

67.5%

Explanation:

Step 1: Write the balanced equation for the electrolysis of water

2 H₂O ⇒ 2 H₂ + O₂

Step 2: Calculate the theoretical yield of O₂ from 17.0 g of H₂O

According to the balanced equation, the mass ratio of H₂O to O₂ is 36.04:32.00.

17.0 g H₂O × 32.00 g O₂/36.04 g H₂O = 15.1 g O₂

Step 3: Calculate the percent yield of O₂

Given the experimental yield of O₂ is 10.2 g, we can calculate its percent yield using the following expression.

%yield = (exp yield / theoret yield) × 100%

%yield = (10.2 g / 15.1 g) × 100% = 67.5%

8 0

2 years ago

Consider the following ionic compounds: CdCO3, Na2S, PbSO4, (NH4)3PO4, and Hg2Cl2. Which compounds will be soluble when added to

Grace [21]

Answer:

a. Na₂S and (NH₄)₃PO₄ .

Explanation:

To know which salts are soluble we need to remember some <em>solubility rules</em>. And apply these as follows:

* All compounds of group 1 (Li⁺, Na⁺, K⁺, etc.) are soluble, Na₂S is soluble.

* All ammonium salts are soluble,

<h3>(NH₄)₃PO₄ is soluble.</h3>

* All Cl⁻, I⁻, Br⁻ are soluble except when are with Ag⁺, Hg₂²⁺, Pb²⁺, Hg₂Cl₂ is <em>insoluble</em>

* Carbonates are insoluble except those with group 1 or ammonium, CdCO₃ is <em>insoluble</em>

* All sulfates are soluble except those with Ca²⁺, Sr²⁺, Ba²⁺, Pb²⁺, Ag⁺. PbSO₄ is <em>insoluble. </em>

Right solution is:

8 0

2 years ago

2) Calculate the percent composition of each element in Mgso,

iogann1982 [59]

Answer:

$\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%$

$\% Ag=93.1\%\\\\\% O=6.9\%$

Explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

$\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%$

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

$\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%$

Best regards!

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2 years ago