What does 2,3-dibromopentane look like?

Chemistry

1 answer:

Shtirlitz [24]3 years ago

6 0

Answer:

The answer to your question is below

Explanation:

Process

1.- To draw an organic molecule, start from the end of the name (pentane)

Pentane has 5 carbons.

2.- Assign numbers the carbons, you can start from the left or to the right

3.- Attach the branches (bromine) in positions 2 and 3

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PbO2 + 4HCl --- PbCl2 + Cl2 + 2H2O who buys electrons and who loses electrons?

SIZIF [17.4K]

Answer: Electrons are taken up by $PbO_2$ and they are lost by $HCl$

Explanation:

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is also called the reaction where the exchange of electrons takes place.

An oxidation reaction is defined as the reaction in which a chemical species loses electrons takes place. In this reaction, the oxidation state of a substance gets increased.

A reduction reaction is defined as the reaction in which a chemical species gains electrons takes place. In this reaction, the oxidation state of a substance gets reduced.

For the given chemical reaction:

$PbO_2+4HCl\rightarrow PbCl_2+Cl_2+2H_2O$

The half-reactions for this redox rection follows:

Oxidation half-reaction: $2HCl\rightarrow ClO_2 + 2e^-$

Reduction half-reaction: $PbO_2+2e^-\rightarrow PbCl_2$

Hence, electrons are taken up by $PbO_2$ and they are lost by $HCl$

8 0

3 years ago

What is the minimum number of liters of co2 measured at stp needed to produce 32 grams of oxygen?

bulgar [2K]

236 I DONT KNOW I AM TOTALLY THAT IS NOT THE ANSWER

4 0

4 years ago

Copper has two naturally occurring isotopes with atomic masses of 62.9296 u () and 64.9278 u (). The atomic mass of copper is 63

natta225 [31]

Answer:

The abundance of first isotope is 69.15 %

The abundance of second isotope is 30.85 %

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$