Lead is the Carbon family of the periodic table.
The combustion of methane, CH4, releases 890.4 kJ/mol. That is, when one mole of methane is burned, 890.4 kJ are given off to the surroundings. This means that the products have 890.4 kJ less than the reactants.
Answer:
Explanation:
AgCl ⇄ Ag⁺ + Cl⁻
m m m
If x mole of AgCl be dissolved in one litre .
[ Ag⁺ ] [ Cl⁻ ] = 1.6 x 10⁻¹⁰
m² = 1.6 x 10⁻¹⁰
m = 1.26 x 10⁻⁵ moles
So solubility of AgCl is 1.26 x 10⁻⁵ moles / L
The answer would be A, 100g since it’s equal
The following Balanced Reaction will take place:
Zn + 2HCl → ZnCl₂ + H₂
In the question, we have 2 moles of Zinc and 3 moles of HCl for this reaction
<u>Amount of HCl required to completely react with 2 moles of Zn:</u>
Since we need 2 moles of HCl for every mole of Zn, we will need 2(2) = 4 moles of HCl for every 2 moles of Zn
<u>Identifying the Limiting Reagent:</u>
But we are only given 3 moles of HCl where we need 4 moles to completely react.
So, since HCl is in less amount, it is the Limiting Reagent
