Using the greatest common factor, it is found that the greatest possible number of footballs that each could have received is of 6.
<h3>Greatest common factor:</h3>
- To find the greatest possible value divided equally between two amounts, we have to find the greatest common factor of the two amounts.
In this problem, the amounts of footballs are of 42 and 54, hence:
42 - 54|2
21 - 27|3
7 - 9
Then, gcf(42, 54) = 2 x 3 = 6, which means that the greatest possible number of footballs that each could have received is of 6.
To learn more about the greatest common factor, you can take a look at brainly.com/question/7527348
Answer:
Step-by-step explanation:
I know you need to use elimination...
But if you Graph the lines the intersection is the answer.
The Answer is (-4,-8)
Remember that there are always 360 degrees in a full circle. Since
(it is a right angle), we can find:
![m\angle2 + m\angle3 = 270^{\circ}](https://tex.z-dn.net/?f=%20m%5Cangle2%20%2B%20m%5Cangle3%20%3D%20270%5E%7B%5Ccirc%7D%20)
Substituting in the values provided in the problem into our equation gives us:
![(x - 7) + 2x = 270](https://tex.z-dn.net/?f=%20%28x%20-%207%29%20%2B%202x%20%3D%20270%20)
![3x - 7 = 270](https://tex.z-dn.net/?f=%203x%20-%207%20%3D%20270%20)
![x = \dfrac{277}{3}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B277%7D%7B3%7D%20)
Given this, we can find the
:
![m\angle3 = 2\Bigg( \dfrac{277}{3} \Bigg) ^{\circ}](https://tex.z-dn.net/?f=%20m%5Cangle3%20%3D%202%5CBigg%28%20%5Cdfrac%7B277%7D%7B3%7D%20%5CBigg%29%20%5E%7B%5Ccirc%7D)
![m\angle3 = \boxed{\dfrac{554}{3}^{\circ} \approx 184.67^{\circ}}](https://tex.z-dn.net/?f=%20m%5Cangle3%20%3D%20%5Cboxed%7B%5Cdfrac%7B554%7D%7B3%7D%5E%7B%5Ccirc%7D%20%5Capprox%20184.67%5E%7B%5Ccirc%7D%7D%20%20)
Answer:
240 units I think
Step-by-step explanation
20 by 2 equal 10 you now know the triangle length
then 4 X 10 equal 40 by 2 equal 20 by 2 equal 40. area of both triangles
20 X 10 equal 200 length of rectangle add both and equal 240.