Question

The numbers a,b,c,d are four consecutive terms of an arithmetic sequence and a+b+c+d=12

Answer 1

The smallest possible product of these four numbers is 59.0625

How to find the smallest possible product of these four numbers?

The equation is given as:

a + b + c + d = 12

The numbers are consecutive numbers.

So, we have:

a + a + 1 + a + 2 + a + 3 = 12

Evaluate the like terms

4a = 6

Divide by 4

a = 1.5

The smallest possible product of these four numbers is represented as:

Product = a * (a + 1) * (a + 2) * (a + 3)

This gives

Product = 1.5 * (1.5 + 1) * (1.5 + 2) * (1.5 + 3)

Evaluate

Product = 59.0625

Hence, the smallest possible product of these four numbers is 59.0625

Read more about consecutive numbers at:

brainly.com/question/10853762

#SPJ1