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Mariana [72]
2 years ago
5

Use the conditional statement to answer the question.

Mathematics
1 answer:
yarga [219]2 years ago
3 0

the correct option is the first one:

"Yes, both the statement and the converse are true."

<h3>How to use the conditional statement?</h3>

Here we have the conditional statement:

"If a number is odd, then it is not divisible by 2"

Now we have the question:

"Can the statement be written as a biconditional and why?"

A biconditional statement is of the form:

"P if and only if Q"

And this means that if any of the two propositions is true, then the other is also true.

In this case:

P = a number is odd.

Q = it is not divisible by 2.

Now, by definition, even numbers are these that are divisible by 2 and odd are these that are not.

Then the statements:

"If a number is odd, then it is not divisible by 2"

"If a number is not divisible by 2, then it is odd"

are true.

So the conditional and the converse are true, this implies that the biconditional statement is also true.

Then the correct option is the first one:

"Yes, both the statement and the converse are true."

If you want to learn more about conditional statements:

brainly.com/question/11073037

#SPJ1

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</span>In Step 1, Hannah wrote \dfrac{d}{dx} (-3+8x) <span> as the sum of two separate derivatives </span>\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x) <span>using the </span><span>sum rule.
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This step is perfectly fine. 

In Step 2, \dfrac{d}{dx}(8x) was kept as it is, and \dfrac{d}{dx}(-3) was rewritten as 0 using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.

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In Step 3, \dfrac{d}{dx} (8x)  was rewritten as \dfrac{d}{dx}(8) \dfrac{d}{dx}(x) supposedly using the constant multiple rule.

The problem is that according to the constant multiple rule, \dfrac{d}{dx}(8x)&#10; should be rewritten as 8 \dfrac{d}{dx}(x) and not as \dfrac{d}{dx}(8)\dfrac{d}{dx}(x).  

<span>Therefore, Hannah made a mistake in this step.</span>
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Answer:

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