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3 years ago

10

You are constructing deck chairs that require 12 2/3 feet of lumber each. How many feet of lumber will you use to make 15 chairs

?

1 answer:

Mrrafil [7]3 years ago

5 0

As each chair needs 12.6667 feet lumber.So 15 chairs will need 15*12.6667=190.0005 lumber

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The production cost for a t-shirt printing company is a function of the number of t-shirts that are printed, t. The function tha

uranmaximum [27]

Answer:

Therefore the company have to print either 47 or 12 t-shirt for its production cost to be $40 or less.

Step-by-step explanation:

Given that,

The function that models the production cost is

$f(t)=0.1 t^2-6t+100$

To find the number of t-shirt, we put f(t)=40 in given function.

∴40= 0.1t²-6t+100

⇒ 0.1t²-6t+100-40=0

⇒0.1 t²- 6t +60=0

⇒t²-60t+600=0

Applying quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ , a=1, b= - 60 and c=600

$t=\frac{-(-60)\pm\sqrt{(-60)^2-4.1.600}}{2.1}$

= 47.32,12.67

≈47, 12

Therefore the company have to print either 47 or 12 t-shirt for its production cost to be $40 or less.

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3 years ago

Work out 5 x 5/6.<br> First correct answer will be marked as brainliest. <br> Thanks!

Gennadij [26K]

Answer:

4+1/6

Step-by-step explanation:

5* 5/6 =25/6 = 4 1/6

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2 years ago

How many unit squares are shaded in a 12 by 12 border grid

torisob [31]

12 ×12 =144 squares. an array is found by multiplying length units by width units. Much like finding the area

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3 years ago

Read 2 more answers

The length of each of the legs of an isosceles triangle is represented by the

lutik1710 [3]

Answer:

10 inches

Step-by-step explanation:

6x-2+6x-2+3x+1=42

12x-4+3x+1=42

15x-3=42

15x=45

x=3

Plug x=3 into 3x+1

3*3+1

9+1=10

Length of base is 10 inches

6 0

3 years ago

The automatic opening device of a military cargo parachute has been designed to open when the parachute is 185 m above the groun

agasfer [191]

Answer:

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

Step-by-step explanation:

For each parachute, there are only two possible outcomes. Either there is damage, or there is not. The probability of there being damage on a parachute is independent of any other parachute, which means that the binomial probability distribution is used to solve this question.

To find the probability of damage on a parachute, the normal distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability of a parachute having damage.

The opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m, which means that $\mu = 185, \sigma = 32$

Equipment damage will occur if the parachute opens at an altitude of less than 100 m, which means that the probability of damage is the p-value of Z when X = 100. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{100 - 185}{32}$

$Z = -2.66$

$Z = -2.66$ has a p-value of 0.0039.

What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes?

0.0039 probability of a parachute having damage, which means that $p = 0.0039$

5 parachutes, which means that $n = 5$

This probability is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.0039)^{0}.(0.9961)^{5} = 0.9807$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.9807 = 0.0193$

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

5 0

3 years ago