Question

What percentage of the original activity in the sample remains after 17.5 days? half life calculation

Answer 1

The percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%.

What is half life?

Half-life is the time required for a quantity to reduce to half of its initial value.

The original activity in the sample that remains after 17.5 days is calculated from half life equation as shown below;

N(t) = No(¹/₂)^t/h

where;

• N(t) is the mass of the substance remaining
• No is the initial mass of the substance
• t is time elapsed = 17.5 days
• h is the half life of the substance
  

percentage of the original activity in the sample remains after 17.5 days;

= N(t) / No x 100%

Thus, the percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%.

Learn more about half life here: brainly.com/question/2320811

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