Evaluate the function would be= x^2-f-x
Answer:
7a 3 −7a+1
Step-by-step explanation: I hope this help.
STEP
1
:
Equation at the end of step 1
((7a3 - 2a) - 2) + (3 - 5a)
STEP
2
:
Polynomial Roots Calculator :
2.1 Find roots (zeroes) of : F(a) = 7a3-7a+1
Polynomial Roots Calculator is a set of methods aimed at finding values of a for which F(a)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 7 and the Trailing Constant is 1.
The factor(s) are:
of the Leading Coefficient : 1,7
of the Trailing Constant : 1
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 1.00
-1 7 -0.14 1.98
1 1 1.00 1.00
1 7 0.14 0.02
Polynomial Roots Calculator found no rational roots
Final result :
7a3 - 7a + 1
<span>Since it's even, the integral from -7 to -1 is the same as the integral from 1 to 7.
</span><span>think about
x^2
from 0..1,its 1/3
from 0..7 its 7^3/3
from -1..7 its 7^3/3+1/3
</span>
<span>from -7..-1 of x^2 its -1/3+7^3/3 to get this without integrating we just do 7^3/3-1/3 which is the integral from 0..7 minus the integral from 0..1
</span><span>So the integral from 1 to 0 f(x) dx = 5 changes to the integral from 0 to 1 f(x) dx = -5 and you add it to the integral from 0 to 7 which is 1 making -4</span>
Answer:
Step-by-step explanation:

No it’s not a right triangle