Answer:
The maximum height of the volleyball is 12.25 feet.
Step-by-step explanation:
The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :
....(1)
The volleyball reaches its maximum height after 0.625 seconds.
For maximum height,
Put 
Now put t = 0.625 in equation (1)

So, the maximum height of the volleyball is 12.25 feet.
Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
<h2>
Answer:</h2>
59 can be cut from the spool.
3 Inches is left over.
<h2>
Step-by-step explanation:</h2>
- 237 feet in 79 yards.
- 237 / 4 = 59.25
- 59 is the whole number, .25 is what is left over.
- .25 feet is 3 inches.
Both solutions are x<span> = 2 and x = -2 are correct
because
</span>when x = 2 , |2| = 2
and
<span>when x = -2, |-2| = 2
hope it helps</span>