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SIZIF [17.4K]
2 years ago
14

13 divided by 25 -0.52 times -107 =-62.48

Chemistry
1 answer:
DanielleElmas [232]2 years ago
8 0
Seval ozhabes Seval your dad will get you the first time in the next few months for the first time I am so happy for you and your family will have a great time together for you and
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Ava and Eddy are discussing the difference between a species being extinct and an endangered species. Ava states that extinction
12345 [234]

In biology the term extinct is used for species which are no longer alive. so here Ava is correct because a species has died out and is not longer alive.

Endangered species are those which are on the urge of being extinct, means they are in danger so the term "endangered"

Ava can also elaborate the terms by taking examples

Dinosaurs are extinct species. They are no longer alive or not found in any part of world. So they are called as extinct.

The term can be used for animal or plant species.

8 0
3 years ago
A clear colorless liquid in an open beaker was heated to boiling. The liquid began to boil at 110°C, and as vapors escaped, the
Vaselesa [24]

Omitted options and they are

a) pure compound.

b. pure element.

c. pure substance.

d. homogeneous solution.

e. heterogeneous solution

Answer:d. homogeneous solution.

Explanation:

Pure substances or  elements or  compounds have a definite and sharp melting or boiling point, Any substance that is not pure is impure and will have different temperature of melting or boiling points.

To this effect, the clear colorless liquid cannot be a Pure substance, element or compound.

We can therefore say that the clear colorless liquid would be a homogeneous solution because a homogeneous solution is a mixture of constituents which completely mixes together such that each constituents cannot be seen with naked eye, When heated to boiling, each constituent in the mixture will give different boiling points.

A heterogeneous Solution, too is a mixture but contains constituents that can be seen and not a clear colourless solution.

Therefore  On the basis of this information, we can say that the material in the beaker was a Homogeneous solution

8 0
4 years ago
How was this purple loosestrife transported to its new ecosystem?
Troyanec [42]
The natural seed spread for purple loosestrife is through water or animals. 

I hope this will help.
3 0
4 years ago
To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o
Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

\pi  r^{2}h ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

r=\frac{d}{2}

=\frac{3.36x10^{2}}{2}

= 168 m

Volume =

=\frac{22\times 168^{2}\times 21.80}{7}

=1.93\times 10^{6} m^{3}

2.Convert ppm to g/m3 and Solve for mass of F-

1ppm = 1g/m^{3}

0.9ppm = 0.9g/m^{3}

Because both ppm and g/m3 are same quantity .

g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}

0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}

mass\ of\ F- =1.740g

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

2Na+F_{2}\rightarrow 2NaF

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g  of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

\frac {84}{38}\times 1.74

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0
3 years ago
The ratio between the force of sliding friction and the normal force of an object is called _____.
Kitty [74]

Answer: The correct answer is C.

Explanation: Frictional force is the contact force which resists the motion of one surface on another.

Mathematically,

f=\mu N

where,

f = frictional force

\mu = Coefficient of friction

N = normal force acting on a body

We need to find the ratio of force of sliding friction ( which is a type of frictional force) and the normal force acting on an object. This will be equal to coefficient of friction.

\mu=\frac{f}{N}

4 0
3 years ago
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