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kotykmax [81]
4 years ago
8

A clear colorless liquid in an open beaker was heated to boiling. The liquid began to boil at 110°C, and as vapors escaped, the

temperature of boiling gradually increased to 115°C, at which point the heating was stopped. On the basis of this information, we can say that the material in the beaker was a
Chemistry
1 answer:
Vaselesa [24]4 years ago
8 0

Omitted options and they are

a) pure compound.

b. pure element.

c. pure substance.

d. homogeneous solution.

e. heterogeneous solution

Answer:d. homogeneous solution.

Explanation:

Pure substances or  elements or  compounds have a definite and sharp melting or boiling point, Any substance that is not pure is impure and will have different temperature of melting or boiling points.

To this effect, the clear colorless liquid cannot be a Pure substance, element or compound.

We can therefore say that the clear colorless liquid would be a homogeneous solution because a homogeneous solution is a mixture of constituents which completely mixes together such that each constituents cannot be seen with naked eye, When heated to boiling, each constituent in the mixture will give different boiling points.

A heterogeneous Solution, too is a mixture but contains constituents that can be seen and not a clear colourless solution.

Therefore  On the basis of this information, we can say that the material in the beaker was a Homogeneous solution

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A balloon contains 30.0 L of helium gas at 1.00 atm. What is the volume of the helium when the balloon rises to an altitude wher
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Answer:

The volume of that ballon would be approximately 1.20 \times 10^2\; \rm L at a pressure of 0.250\; \rm atm.

Explanation:

Let V_1 and P_1 be the volume and pressure of the gas before the change.

By Boyle's Law, the volume of an ideal gas is inversely proportional to its pressure. In other words, if V_2 and P_2 represent the volume after the change, then V_1 \cdot P_1 = V_2 \cdot P_2.

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\begin{aligned}& V_1\cdot P_1 = V_2 \cdot P_2 \\ & \implies V_2 = \frac{V_1 \cdot P_1}{P_2} = \frac{P_1}{P_2} \cdot V_1\end{aligned}.

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