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kotykmax [81]
4 years ago
8

A clear colorless liquid in an open beaker was heated to boiling. The liquid began to boil at 110°C, and as vapors escaped, the

temperature of boiling gradually increased to 115°C, at which point the heating was stopped. On the basis of this information, we can say that the material in the beaker was a
Chemistry
1 answer:
Vaselesa [24]4 years ago
8 0

Omitted options and they are

a) pure compound.

b. pure element.

c. pure substance.

d. homogeneous solution.

e. heterogeneous solution

Answer:d. homogeneous solution.

Explanation:

Pure substances or  elements or  compounds have a definite and sharp melting or boiling point, Any substance that is not pure is impure and will have different temperature of melting or boiling points.

To this effect, the clear colorless liquid cannot be a Pure substance, element or compound.

We can therefore say that the clear colorless liquid would be a homogeneous solution because a homogeneous solution is a mixture of constituents which completely mixes together such that each constituents cannot be seen with naked eye, When heated to boiling, each constituent in the mixture will give different boiling points.

A heterogeneous Solution, too is a mixture but contains constituents that can be seen and not a clear colourless solution.

Therefore  On the basis of this information, we can say that the material in the beaker was a Homogeneous solution

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A 34.53 ml sample of a solution of sulfuric acid, h2s04, reacts with 27.86 ml of 0.08964 m naoh solution. calculate the molarity
Gnoma [55]
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol 
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol 
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol 
molarity of H₂SO₄ is 0.03617 M
6 0
3 years ago
Describe how you use conduction to make your s'mores
telo118 [61]

Answer:

the hot fire is depositing heat directly on to the marshmello, heating/cooking it. the hot marshmello then is placed onto chocolate, melting it but idk if that part matters.

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4 years ago
The hybridization for the B in Bcl3 is ?
Phoenix [80]

Answer:

sp²

Explanation:

You need to look at how many electron orbitals around the atom.  Looking at the structure below, you can see that there are three electron orbitals.  This gives you an sp² hybridization.

6 0
3 years ago
A balloon is filled with 0.250 mole of air at 35°C. If the volume of the balloon is 6.23 liters, what is the absolute pressure o
ruslelena [56]

Answer:

102.807 kPa

Explanation:

There are some assumptions to be made in the answer. The air inside the balloon acts as an ideal gas at a given temperature conditions.

Using the combined ideal gas equation.

PV = nRT\\

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V= volume of air inside the balloon (6.23 L= 6.23 * 10⁻³ m³)

n= moles of gas(air). (0.250 mol)

R= Universal gas constant ( 8.314 J / mol·K)

T= Temperature in Kelvin

T= 35 + 273.15 = 308.15 K

So, P = \frac{nRT}{V}

P = \frac{0.250 * 8.314 * 308.15}{6.23 * 10^{-3} }

P= 102.807 * 10³ Pa

P= 102.807 kPa

3 0
3 years ago
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Reason:
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5 0
3 years ago
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