Answer:
For length of side = 3 cm
Area of the square = 9 cm²
For length of side = 10.5 cm
Area of the square = 110.25 cm²
For length of side = π cm
Area of the square = 9.869 cm²
Step-by-step explanation:
The area of a square is given as :
Area = Side²
therefore,
For length of side = 3 cm
Area of the square = ( 3 cm )² = ( 3 × 3 ) cm² = 9 cm²
For length of side = 10.5 cm
Area of the square = ( 10.5 cm )² = ( 10.5 × 10.5 ) cm² = 110.25 cm²
For length of side = π cm
Area of the square = ( π cm )²
= ( π × π ) cm²
= 3.14² cm² [π = 3.14]
= 9.869 cm²
Answer:
4 minutes
Step-by-step explanation:
looks at the 8 gallon line and follow it over to the corresponding minute line
Answer:
The score that separates the lower 5% of the class from the rest of the class is 55.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

Find the score that separates the lower 5% of the class from the rest of the class.
This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.


The score that separates the lower 5% of the class from the rest of the class is 55.6.
Answer:
-1,1 0,-3
Step-by-step explanation:
start at -2, 5 and go down 4 right 1.
Rinse and repeat