KN bisects ZJKM. If mZNKJ = 7x-9 and m2JKM = x + 3, find m2JKN.
1 answer:
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The equation is a function
Explanation:
Given that the graph contains the coordinates ,
,
and
We need to determine whether the equation is a function.
To determine the equation is a function, let us substitute the coordinates in the equation and check whether it satisfies the equation.
Let us substitute the coordinate in the equation
Thus, we have,
Thus, the coordinate satisfies the equation
Substituting the coordinate in the equation, we have,
Thus, the coordinate satisfies the equation
Substituting the coordinate in the equation
Thus, the coordinate satisfies the equation
Substituting the coordinate in the equation, we get,
Thus, the coordinate satisfies the equation
Hence, the coordinates ,
,
and
satisfies the equation
Thus, the equation is a function.
Answer:
The domain is {x : x ∈ R} or (-∞ , ∞)
Step-by-step explanation:
* Lets explain how to find the domain
- The domain of the function is the values of x which make the
function defined
- The quantity under the square root must be ≥ 0 because there is
no square root for negative value
* Lets solve the problem
∵ f(x) = √(x² - x + 6)
∴ The value of (x² - x + 6) must be greater than or equal zero because
there is no square root for negative value
- Graph the function to know which values of x make the quantity
under the root is negative that means the values of x which make
the graph under the x-axis
∵ The graph doesn't intersect the x-axis at any point
∵ All the graph is above the x-axis
∴ There is no value of x make f(x) < 0
∴ x can be any real number
∴ The domain of f(x) is all real numbers
∴ The domain is {x : x ∈ R} or (-∞ , ∞)
