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2 years ago

Which statement is true ?

Mathematics

1 answer:

podryga [215]2 years ago

7 0

Answer:

Step-by-step explanation:

plan 2 grows exponentially so it grows at a faster rate than plan 1, even though plan 1 starts with 100 members

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Need help Math Question Multiple Choice!

erica [24]

Given :

A function f(x) for different range of x.

To Find :

The value of f( -3 ) .

Solution :

We have to find the value of function at x = -3.

Now, in the given figure -3 lies in range x ≤ -2 and definition of function at that range is :

$f(x) = \dfrac{2}{x}$

So, putting value of x = -3 in above equation, we get :

$f(-3) = \dfrac{2}{-3} \\\\f(-3) = \dfrac{-2}{3}$

Hence, this is the required solution.

8 0

3 years ago

Evaluate the expression 6/5x when x=20

Sindrei [870]

Answer:

Step-by-step explanation:

6 divided by 5 times 20 =24

6/5*20= 24

7 0

3 years ago

Find the distance between each pair of points. round your answer to the nearest tenth, if necessary. (-8, -5), (-4, 3)

Anuta_ua [19.1K]

The answer would be 8.9

8 0

3 years ago

Help me on this thanks

g100num [7]

The answer here is C.

Explanation:
24 feet / 10 inches = 28.8
Then take 60 feet and divide 28.8 by it:
2.08 feet
Then convert 2.08 ft to inches: 24.96 inches

8 0

3 years ago

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

3 years ago