The discontinuity occurs when the denominator is equal to zero, as it has "infinite" slope, and thus is not a real value or point.
x^2+x-12
x^2+4x-3x-12
x(x+4)-3(x+4)
(x-3)(x+4)
So discontinuities occur when x=-4 and x=3
That’s hard I’m just typing stuff to get points lol
Answer:
3 boxes
Step-by-step explanation:
2 out of 16 boxes are flawed. So the unit rate is
Now, to find number of flawed boxes is 24 checkings, we need to multiply the unit rate (1/8) by 24. So:
The answer is 3
We are given the line 7-4x=7y.
If we write this line in the form y=mx+k, then m is the slope of the line.
7-4x=7y
7y=-4x+7
y=(-4/7)x+1
the slope of the line is -4/7
Any line parallel to this line must also have a slope equal to -4/7.
We want precisely the one passing through (2, 0) and having slope -4/7.
Using the point-slope form of the equation of a line:
(y-0)=-4/7(x-2)
y=(-4/7)x+8/7
Answer: y=(-4/7)x+8/7
another form is 4x+7y-8=0
y = 3 is the line of reflection
Under a reflection in a line, corresponding points of the original and it's image should be equidistant from the line of reflection
y = 3 is the horizontal line passing through all the points with a y-coordinate of 3
A is 1 unit above and A' is 1 unit below the line
B is 3 units above and B' is 3 units below
C is 1 unit below and C' is 1 unit above
D is 1 unit below and D' is 1 unit above
The vertices of the figure and the image are all equidistant from y = 3
