Question

f a ball is thrown into the air with an initial velocity of 46 ft/s, its height in feet after t seconds is given by y

Answer 1

The ball  that is thrown into the air with a velocity of 44 ft/s, its height in feet t seconds later is given by the following equation:

y=46 ft/s * t - (32.17 ft/s² * t²/2)

The height in (ft) at a time (t) of a body that has been thrown with a certain velocity and is in vertical motion is given by the following equation:

y = vi * t - (g* t²/2)

Where:

• y = height
• vi = initial velocity
• g = gravity
• t = time

Information about the problem:

• vi = 46 ft/s
• g = 32.17 ft/s²
• y =?
• t = t

Applying the height formula we get:

y = vi * t - (g* t²/2)

y = 46 ft/s * t - (32.17 ft/s² * t²/2)

What is the vertical upward launch?

It is the movement described by an object that has been thrown vertically upwards in which the height and the effect of the force of the earth's gravity on the thrown object are considered.

Learn more about vertical upward launch at: brainly.com/question/14532699

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