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neonofarm [45]
3 years ago
12

How is the pressure of a gas related to its concentration of particles?A) Pressure will expand a gas, enlarging its volume and r

educing its density and concentration of particles. B) Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles. C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles. Eliminate D) Pressure will accelerate a gas, extending its volume and allowing a smaller density and concentration of particles.
Physics
1 answer:
Lesechka [4]3 years ago
8 0

Answer:

C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.

Explanation:

At constant temperature, pressure and volume are inversely related.

P V = constant

\Rightarrow P \propto \frac{1}{V}

As the pressure increases, the gas compresses, the particles come closer reducing the volume of gas.

As we know, with decrease in volume, density increases.

Density = \frac{Mass}{Volume}

Density \propto \frac{1}{Volume}

Thus, the pressure of a gas is directly related to concentration of particles. Increase in pressure causes increase in concentration of the particles.

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Two sides of a parallelogram are in the ratio 5 : 3. If its perimeter is 64 cm, find the lengths of its sides.​
Xelga [282]

Answer: 32

Explanation:

4 0
3 years ago
A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a sp
dusya [7]

from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"

here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?

Answer:

(A) 26 m/s

(B) 32.4 m

(C) v = 15.4 m/s

Explanation:

initial speed (u) = 6.4 m/s

acceleration due to gravity (a) = 9.9 m/s^[2}

time (t) = 2 s

(A)   What is its speed after falling for 2.00s?

  from the equation of motion v = u + at we can get the speed

v = 6.4 + (9.8 x 2) = 26 m/s

(B) How far does it fall in 2.00s?

  from the equation of motion s=ut+0.5at^{2} we can get the distance covered

s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)

s = 12.8 + 19.6 = 32.4 m

c) What is the magnitude of its velocity after falling 10.0m?

from the equation of motion below we can get the velocity

v^{2} = u^{2} + 2as\\v^{2} = 6.4^{2} + (2x9.8x10)\\V^{2} = 236.96\\v = \sqrt{236.96}

v = 15.4 m/s

7 0
3 years ago
A 10- kilogram block is pushed across a horizontal surface with a horizontal force of 20 N against a friction force of 10 N. The
Temka [501]

Answer:

1m/s^2

Explanation:

Mass of block=10 kg

Applied horizontal force =F=20 N

Friction force=f=10 N

We have to find the acceleration of block.

Net force=Applied horizontal force-friction force

ma=F-f

Where F= Horizontal force

f=Friction force

m=Mass of object

a=Acceleration of object

10a=20-10=10

a=\frac{10}{10}=1 m/s^2

Hence, the acceleration of the block=1m/s^2

4 0
3 years ago
1. 1. are the charged parts of an atom.
victus00 [196]

Answer:

» e. Electrons and protons

Explaination :

Electrons are negatively charged and protons are positively charged.

  • The neutrons do not have a charge.
5 0
2 years ago
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It’s me again lol you’re questions are simple the formula is given in the triangle
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