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neonofarm [45]
3 years ago
12

How is the pressure of a gas related to its concentration of particles?A) Pressure will expand a gas, enlarging its volume and r

educing its density and concentration of particles. B) Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles. C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles. Eliminate D) Pressure will accelerate a gas, extending its volume and allowing a smaller density and concentration of particles.
Physics
1 answer:
Lesechka [4]3 years ago
8 0

Answer:

C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.

Explanation:

At constant temperature, pressure and volume are inversely related.

P V = constant

\Rightarrow P \propto \frac{1}{V}

As the pressure increases, the gas compresses, the particles come closer reducing the volume of gas.

As we know, with decrease in volume, density increases.

Density = \frac{Mass}{Volume}

Density \propto \frac{1}{Volume}

Thus, the pressure of a gas is directly related to concentration of particles. Increase in pressure causes increase in concentration of the particles.

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You are directed to set up an experiment in which you drop, from shoulder height, objects with similar surface areas but differe
tangare [24]

Answer: c. they will hit the ground at the same time

Explanation:

The volume of both objects is almost the same, so the force of friction will be the same in each one, so we can discard it.

Now, when yo drop an object, the acceleration of the object is always g = 9.8m/s^2 downwards, independent of the mass of the object.

So if you drop two objects with the same volume but different mass, because the acceleration is the same for both of them, they will hit the ground at the same time, this means that the density of the object has no impact in how much time the object needs to reach the floor.

So the correct option is c

3 0
3 years ago
The initial speed of a body is 7.1 m/s. What is its speed after 2.23 s if it accelerates uniformly at 2.64 m/s 2 ? Answer in uni
Nana76 [90]

13.0m/s

1.2m/s

Explanation:

Given parameters:

Initial speed of the body = 7.1m/s

time taken = 2.23s

Acceleration = 2.64m/s²

Unknown:

Final speed = ?

Solution:

Acceleration is the rate of change of velocity with time.

   a = \frac{V - U}{T}

a  = acceleration

V = final speed

U = initial speed

T = time taken

  Input the variables and solve for V;

 

   2.64 = \frac{V - 7.1}{2.23}  

  V - 7.1 = 5.9                              expression 1

  V = 5.9 + 7.1 = 13.0m/s

B

Using the same parameters, the speed after a uniform deceleration of -2.64m/s², the negative sign implies deceleration;

 from expression 1;

           V - 7.1  = -5.9

           V = -5.9 + 7.1 = 1.2m/s

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

5 0
3 years ago
Which of the following is true about Viscosity of liquids:
White raven [17]
Viscosity of liquids is essentially the 'thickness' of the liquid. For instance, honey and water have different viscosities. Honey has a higher one and therefore, liquids with high viscosity do not flow as well as liquids with low viscosity (water).
4 0
3 years ago
Read 2 more answers
What does the potential energy and kinetic energy of an object depend on ?
alexdok [17]

Answer:

Both, potential energy and kinetic energy depends on mass. The higher the mass, the higher the energy. However, the difference is that potential energy depends on vertical height whereas kinetic energy depends on the velocity.

Explanation:

From the formula we can see that;

Potential Energy = mass* gravitational acceleration *vertical height.

Kinetic Energy = 0.5 * mass * (velocity)^2

4 0
3 years ago
A pitcher throws a 0.145-kg baseball at a velocity of 30.0m/s. How
nata0808 [166]

Answer: 65.25 J

Explanation:

Kinetic Energy K.E. = 1/2 * m * v^2 ; where m is the mass of the body and v is the velocity of the body ; K.E. = 1/2 * 0.145 * 30 * 30 = 65.25 Joules

6 0
3 years ago
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