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jeyben [28]
3 years ago
13

A hockey puck sliding on a frictionless surface strikes a box at rest. After the collision, the two objects stick together and m

ove at some final speed.
Which of the statements describes the change in momentum and energy of the puck during the collision?

a) The puck loses some, but not all, of its original momentum and mechanical energy.
b) One cannot determine if the momentum or energy of the puck is conserved without knowing the final velocities and masses of the two objects.
c) The puck loses some momentum in the collision but conserves its mechanical energy.
d) The puck conserves its original momentum but loses all of its mechanical energy.
e) The puck conserves its original momentum and mechanical energy.
f) The puck conserves its original momentum but loses some, but not all, of its mechanical energy.
Physics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

Answer:

f) The puck conserves its original momentum but loses some, but not all, of its mechanical energy.

 Explanation:

It is a case of perfectly inelastic collision . So momentum will be conserved because no external force acts on them during the collision . But there will be loss of energy ( kinetic energy ) . It will be in the form of sound or heat that is produced during collision. They will still have some kinetic energy even after the collision.

 

Explanation:

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Answer:

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Problem #2: An apple is thrown upward with an initial velocity of +24.0 m/s. a. Sketch the apple's trip and label what you know.
bogdanovich [222]

Answer:

The answer is below

Explanation:

a) The initial velocity (u) = 24 m/s

We can solve this problem using the formula:

v² = u² - 2gh

where v = final velocity, g= acceleration due to gravity = 9.8 m/s², h = height.

At maximum height, the final velocity = 0 m/s

v² = u² - 2gh

0² = 24² - 2(9.8)h

2(9.8)h = 24²

2(9.8)h = 576

19.6h = 576

h = 29.4 m

b) The time taken to reach the maximum height is given as:

v = u - gt

0 = 24 - 9.8t

9.8t = 24

t = 2.45 s

The total time needed for the apple to return to its original position = 2t = 2 * 2.45 = 4.9 s

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3 years ago
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Answer:

8m/s²

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The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

<h3>Total capacitance of the circuit</h3>

The total capacitance of the circuit is calculated as follows;

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1/Ct = 0.25833

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Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

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Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

Learn more about capacitors here:  brainly.com/question/13578522

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