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jeyben [28]
4 years ago
13

A hockey puck sliding on a frictionless surface strikes a box at rest. After the collision, the two objects stick together and m

ove at some final speed.
Which of the statements describes the change in momentum and energy of the puck during the collision?

a) The puck loses some, but not all, of its original momentum and mechanical energy.
b) One cannot determine if the momentum or energy of the puck is conserved without knowing the final velocities and masses of the two objects.
c) The puck loses some momentum in the collision but conserves its mechanical energy.
d) The puck conserves its original momentum but loses all of its mechanical energy.
e) The puck conserves its original momentum and mechanical energy.
f) The puck conserves its original momentum but loses some, but not all, of its mechanical energy.
Physics
1 answer:
coldgirl [10]4 years ago
3 0

Answer:

Answer:

f) The puck conserves its original momentum but loses some, but not all, of its mechanical energy.

 Explanation:

It is a case of perfectly inelastic collision . So momentum will be conserved because no external force acts on them during the collision . But there will be loss of energy ( kinetic energy ) . It will be in the form of sound or heat that is produced during collision. They will still have some kinetic energy even after the collision.

 

Explanation:

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A newly discovered particle, the SPARTYON, has a mass 945 times that of an electron. If a SPARTYON at rest absorbs an anti-SPART
Gennadij [26K]

Answer:

\nu =1166\times 10^{20}Hz  

Explanation:

We have given the rest mass of SPARTYON = 945 times of mass of electron

We know that mass of electron =9.11\times 10^{-31}kg

So mass of SPARTYON =945\times 9.11\times 10^{-31}=8608.95\times 10^{-31}kg

Speed of light c=3\times 10^8m/sec

According to Einstein equation energy is given by

E=mc^2=8608.95\times 10^{-31}\times (3\times 10^{8})^2=77480.55\times 10^{-15}j

Now according to planks's rule

Energy is given by

E=h\nu , here h is plank's constant h=6.6\times 10^{-34}

So 77480.55\times 10^{-15}=6.6\times 10^{-34}\nu

\nu =1166\times 10^{20}Hz  

3 0
3 years ago
Charges q3 and q5 are now replaced by two charges, q2 and q6, having equal magnitude and sign (-3.4 μC). Charge q2 is located at
ivanzaharov [21]
I believe the answer would be zero because the q1 and q2 are equal on opposite sides and it

hope this helps
3 0
3 years ago
Joshua programs a robotic arm to place a block in a box by following the sequence of commands in the table. A 2-column table wit
seraphim [82]

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Explanation:

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5 0
2 years ago
What is the value of the boltzmann constant of 1.7 moles of gas at 290 K that has an average kinetic energy of 1.4 MJ? A. 7x10^-
fredd [130]

Answer:

The value of  of the Boltzmann constant is 3.14\times 10^{-23} J/K.

Explanation:

Generally the formula for average kinetic energy of a molecule :

K.E=\frac{3}{2}kT

where,

k = Boltzmann’s constant

T = temperature = 290 K

Given:

Number of molecules in 1.7 moles:

1.7\times 6.022\times 10^{23} molecules=1.0237\times 10^{24} molecules

Average kinetic energy of 1.7 moles = 1.4 MJ =1.4\times 10^6 J

Average kinetic energy of 1 molecule = \frac{1.4\times 10^6 J}{1.023\times 10^{24}} =1.3675\times 10^{-18} J

1.3675\times 10^{-18} J=\frac{3}{2}\times k\times (290K)

k=3.14\times 10^{-23} J/K

8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Nostrana [21]

Don't look now, but the question GIVES you the formula to use, and it GIVES you the numbers to plug into the formula.

The formula to use to find the distance covered by the sound is

<em>Speed = (distance) / (time)</em>

They also give you:

speed = 330 m/s

time = 0.40 second

Stuff the numbers into the formula:

330 m/s = (Distance) / (0.40 second)

Multiply each side by (0.40 second), and you get:

(330 m/s) / (0.4 second) = Distance

<em>825 meters = Distance</em>

4 0
3 years ago
Read 2 more answers
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