Is the inequality always, sometimes, or never true?

Mathematics

1 answer:

MariettaO [177]1 year ago

7 0

Answer:

Never true

Step-by-step explanation:

2x - 5 < 2(x - 3) first multiply 2 with the inside the parenthesis

2x - 5 < 2x - 6

now when we simplify the inequality 2x on the both sides will be eliminated and we will be left with:

(-5) < (-6) which cannot be true because (-5) is closer to 0 in number line so it's bigger then (-6) not smaller

Therefore the answer is "Never true"

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Fill in the signs to make true 9 4 7 3 = 15

KonstantinChe [14]

9- 4+ 7 +3 = 15

5+7+3=15

12+3=15

15=15

7 0

4 years ago

A market survey shows that half the owners of Sorey State Boogie Boards became disenchanted with the product and switched to C&a

OlgaM077 [116]

Answer:

$\left[\begin{array}{ccc}\dfrac{1}{2} &\dfrac{1}{2}\\\\\dfrac{1}{4}&\dfrac{3}{4}\end{array}\right]$

Step-by-step explanation:

Let 1 = Sorey State, and 2 = C&T

Half the owners of Sorey State Boogie Boards became disenchanted with the product and switched to C&T Super Professional Boards the next surf season.

This means half moved from State 1 to State 2.

Three quarters of the C&T Boogie Board users remained loyal to C&T, while the rest switched to Sorey State.

The rest $(1-\frac{3}{4}= \frac{1}{4})$ moved from State 2 to State 1.

The Markov Transition Matrix is presented below:

$\left\begin{array}{ccc}\\\\\\$Sorey State&1\\\\C\&T&2\end{array}\right\left[\begin{array}{ccc}$Sorey State&C\&T\\1&2\\------&------\\\dfrac{1}{2} &\dfrac{1}{2}\\\\\dfrac{1}{4}&\dfrac{3}{4}\end{array}\right]$