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xz_007 [3.2K]
2 years ago
6

A bank lets its constomers

Engineering
1 answer:
mafiozo [28]2 years ago
7 0

Answer:

1/1260

Explanation:

Since ther PIN consists of 2 characters with one being an alphabet while the other is a letter;

There are 26 alphabets and 10 possible digits. Thus;

Total characters = 36 characters.

Probability of someone correctlly guessing a bank Customer's PIN in the first attempt if no repeats are allowed is; 1/(36C1 * 35C1) = 1/1260

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20. It is important to keep a copy of your written plan and safety records off-site.
Verdich [7]

Answer:

A

Explanation:

Incase you need to re-read or you need to refresh your memory.

Also, Incase something happens, you will have the rules and guidelines.

4 0
3 years ago
. The job of applications engineer for which Maria was applying requires (a) excellent technical skills with respect to mechanic
Hitman42 [59]

Answer:

  1. Tell us about your self
  2. Are your confident that you are the right candidate for this position
  3. why should i hire you
  4. Do you like working under supervision
  5. How do you like to work ( in a group or individually )
  6. What is your ultimate workplace goal
  7. what are your future plans
  8. What do you expect from the Organization when given the job
  9. Do you like taking on critical problems
  10. How long can you work in this position

Explanation:

For a job of applications engineer which require excellent technical skills, commitment  to working , ability to deal well and confidently with customers a willingness to travel and very intelligent and well-balanced personality.

The ten questions you should ask Maria to determine if she is qualified for the job are :

  1. Tell us about your self ( functions you have )
  2. Are your confident that you are the right candidate for this position
  3. why should i hire you
  4. Do you like working under supervision
  5. How do you like to work ( in a group or individually )
  6. What is your ultimate workplace goal
  7. what are your future plans
  8. What do you expect from the Organization when given the job
  9. Do you like taking on critical problems
  10. How long can you work in this position
5 0
3 years ago
A train travels 650 meters in 25 seconds. What is the train's velocity?
frosja888 [35]

The train is traveling 26 meters A second .

3 0
3 years ago
There are little to no benefits to supplementary field identification programs
VashaNatasha [74]

Answer:

True, supplementary field identification programs tend to limit the use of routine programs that target service delivery using routine systems.

Explanation:

When supplementary field identification programs are applied in a study, they have damaging effects to other systems and programs already in progress targeting certain/similar variables in a study group.Such programs are initiated to boost the already existing systems of programs that are in continuous application( routine basis). As a supplement , we expect more positive results in the rates per the variables included in a study.However, results has proved the opposite.For example, supplementary immunization activities applied in programs targeting demographic and health systems services reveled that such programs reduce the probability of receiving the services provided by other routine health systems conducting continuous vaccination programs to the target groups.

4 0
4 years ago
Air enters the combustor of a jet engine at p1=10 atm, T1=1000°R, and M1=0.2. Fuel is injected and burned, with a fuel/air mass
snow_lady [41]

Answer:

M2 = 0.06404

P2 = 2.273

T2 = 5806.45°R

Explanation:

Given that p1 = 10atm, T1 = 1000R, M1 = 0.2.

Therefore from Steam Table, Po1 = (1.028)*(10) = 10.28 atm,

To1 = (1.008)*(1000) = 1008 ºR

R = 1716 ft-lb/slug-ºR cp= 6006 ft-lb/slug-ºR fuel-air ratio (by mass)

F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga

For the air q = cp(To2– To1)

(Exit flow – inlet flow) – choked flow is assumed For M1= 0.2

Table A.3 of steam table gives P/P* = 2.273,

T/T* = 0.2066,

To/To* = 0.1736 To* = To2= To/0.1736 = 1008/0.1736 = 5806.45 ºR Gives q = cp(To* - To) = (6006 ft-lb/sluga-ºR)*(5806.45 – 1008)ºR = 28819500 ft-lb/slugaSetting equal to equation 1 above gives 28819500 ft-lb/sluga= FA*(4.5 x 108) ft-lb/slugaFA =

F/A = 0.06404 slugf/slugaor less to prevent choked flow at the exit

5 0
3 years ago
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