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Mnenie [13.5K]
3 years ago
13

Transmission cleaners are used: A) Only in conjunction with fuel system cleanersB) Only in the colder monthsC) By themselvesD) I

n conjunction with a transmission fluid exchange
Engineering
2 answers:
valentina_108 [34]3 years ago
5 0

Answer: D

Explanation: When you change your transmission fluid you change your filter. When you do that you clean where the filter was. Then you can put the new filter on and the new fluid.

irinina [24]3 years ago
3 0

Explanation: When you change your transmission fluid you change your filter. When you do that you clean where the filter was. Then you can put the new filter on and the new fluid.

is correct

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What’s the number of gold atoms in a nanogram? a picogram?
zvonat [6]

Answer :

The number of gold atoms in nanogram is, 3.057\times 10^{12}

The number of gold atoms in picogram is, 3.057\times 10^{9}

Explanation :

As we know that the molar mass of gold is, 196.97 g/mole. That means, 1 mole of gold has 196.97 grams of mass of gold.

As we know that,

1 mole contains 6.022\times 10^{23} number of atoms.

First we have to determine the number of gold atoms in a nanogram.

As, 196.97 grams of gold contains 6.022\times 10^{23} number of gold atoms

And, 1 grams of gold contains \frac{1g}{196.97g}\times (6.022\times 10^{23}) number of gold atoms

So, 10^{-9} nanograms of gold contains \frac{1g}{196.97g}\times (10^{-9})\times (6.022\times 10^{23})=3.057\times 10^{12} number of gold atoms

The number of gold atoms in nanogram is, 3.057\times 10^{12}

Now we have to determine the number of gold atoms in a picogram.

As, 196.97 grams of gold contains 6.022\times 10^{23} number of gold atoms

And, 1 grams of gold contains \frac{1g}{196.97g}\times (6.022\times 10^{23}) number of gold atoms

So, 10^{-12} picograms of gold contains \frac{1g}{196.97g}\times (10^{-12})\times (6.022\times 10^{23})=3.057\times 10^{9} number of gold atoms

The number of gold atoms in picogram is, 3.057\times 10^{9}

8 0
3 years ago
Prepare deflection angles for staking the curves in problem 2-2. In every example assume that Sta. P.I. = 37+53.21. Carry the re
weeeeeb [17]

Answer:

ya mom

Explanation:

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3 years ago
Find the cost of fencing a rectangular park of length 10 m and breadth 5 m at the rate of? 10 per metre.
ser-zykov [4K]
It costs 300
Perimeter = 2(L+B)
2(10+5)
2(15) = 30
10 — 1metre
X — 30metres
30metres = 300

Hope that helps :)
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2 years ago
Was rachel and ross on a break
yaroslaw [1]

Answer:

yes they were on a break

Explanation:

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elixir [45]

Answer:

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Explanation:

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