1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Flura [38]
2 years ago
13

What type of motion would produce positive acceleration in an object? What type of motion would produce negative acceleration?

Physics
1 answer:
Bumek [7]2 years ago
4 0

Answer:

positive acceleration: releasing an object from a height - acceleration due to the force of gravity, the speed of the object will increase as it falls

negative acceleration: applying breaks on the tires to slow down the car - deceleration due to frictional forces

You might be interested in
What is wind shear? When wind is moving extremely fast in one direction When wind is moving with a circular motion When two wind
AlexFokin [52]

Answer:

C) When wind direction or wind speed changes with altitude :)

Explanation:

7 0
4 years ago
What happens to the current in a circuit when the resistance is increased
VikaD [51]

then the current will decrease.

hope this helps :)

5 0
3 years ago
(a) Calculate the magnitude of the gravitational force exerted on a 445-kg satellite that is a distance of 1.77 earth radii from
victus00 [196]

Answer:

a)1396.52 N

b)1396.52 N

c)a_{satellite}= 3.13 m/sec^2

d)a_{earth}=2.32\times10^{-22} m/s^2

Explanation:

The force experienced by the satelite is giveb by

F= \frac{Gm_{satellite}m_{earth}}{r^2} \\

m_{satellite}= 445 Kg

m_{earth}= 6×10^24 Kg

radius r= 1.77Re= 1.77×6.38×10^6 m

now putting values we get

F= \frac{6.67\times10^{-11}(445)(6\times10^24)}{(1.77\times6.38\times10^6)^2}

⇒F= 1396.52 N

now,

a_{satellite}= \frac{F}{m_{satellite}}

a_{satellite}= \frac{1396.52}{445}

a_{satellite}= 3.13 m/sec^2

also,

a_{earth}= \frac{F}{m_{earth}}

a_{earth}= \frac{1396.52}{(6\times10^24)}

a_{earth}=2.32\times10^{-22} m/s^2

3 0
3 years ago
How do you calculate the speed of a wave? Write and label the formula.
beks73 [17]

Answer:

Wavelength x Frequency

5 0
3 years ago
Read 2 more answers
A stationary charge is located between the poles of a horseshoe magnet. Is a magnetic force excerted of the charge? why?
vredina [299]

A stationary charge is located between the poles of a horseshoe magnet. The magnetic force exerted by the charge is zero.

<h3>What is charge?</h3>

Charge is the physical property of matter which cause a particle to attract or repel when placed in its field.

A stationary charged particle does not interact with a static magnetic field. A charge placed in a magnetic field experiences a magnetic force. There will be no magnetic force acting on a stationary charge. The charge must be moving in order to have magnetic force on it.

Thus, the magnetic force exerted by the charge is zero.

Learn more about charge.

brainly.com/question/19886264

#SPJ4

7 0
2 years ago
Other questions:
  • Where does energy go when an object hits the ground?
    10·1 answer
  • Water is the most common polar solvent. All of the following will dissolve, or be soluble, in water except _________.
    7·2 answers
  • If the rocket burns its fuel in a time of 50.0 s and the relative speed of the exhaust gas is vex = 2100 m/s, what must the mass
    10·1 answer
  • An RV is traveling 60 km/h along a highway at night. A boy sitting near the driver of the RV turns a flashlight on and shines it
    15·1 answer
  • 1. In a Millikan type experiment, two horizontal plates are 2.5 cm apart. A latex sphere of
    11·1 answer
  • Doubling an object’s height will have what effect on its potential energy due to gravity?
    11·1 answer
  • How can Newton's third law describe the forces affecting a rocket as it
    5·2 answers
  • I need help plz<br> Help meh
    9·2 answers
  • __________ is extremely resistant to oxidation and rusting.
    13·1 answer
  • I NEED HELP ASAP!!!
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!