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jasenka [17]
3 years ago
9

What is wind shear? When wind is moving extremely fast in one direction When wind is moving with a circular motion When two wind

s are moving in opposite directions with different speeds When two winds are moving very quickly upwards When wind is entering a tornado?
Physics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

C) When wind direction or wind speed changes with altitude :)

Explanation:

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Assuming the atmospheric pressure is 1 atm at sea level, determine the atmospheric pressure at Badwater (in Death Valley, Califo
tiny-mole [99]

Answer:

Atmospheric pressure at Badwater is 1.01022 atm

Explanation:

Data given:

1 atmospheric pressure (Pi) = 1.01 * 10^{5} Pa

Elevation (h) = 86m

gravity (g) = 9.8 m/s2

Density of air P = 1.225 kg/m3

Therefore pressure at bad water Pb = Pi + Pgh

Pb = (1.01 * 10^{5}) + (1.225 * 9.8 * 86)

Pb = (1.01 * 10^{5}) + 1032.43 = 102032 Pa

hence:

Pb = 102032 /1.01 * 10^{5} = 1.01022 atm

4 0
3 years ago
a sound intensity of 70 dB is observed a distance of d from the source of sound. what sound intensity would be observed at a dis
elixir [45]

Answer:

Correct option is

B

16dB

Sound level at A is ⊥o⊥B

If the intensity of sound at A 4 cm away from the source is I

A

then.

⊥o=10log

I

o

I

A

Where I

o

=10

−12

w m

−2

⇒⊥=log

10

−12

I

A

⇒

10

−12

I

A

=10

⇒I

A

=10

−11

wm

−2

If the source (s) is emmitting the sound energy of power P

I

A

=

4×(4)

2

P

⇒P=10

−11

×64π w

⇒ Intensity of sound (I

B

) ar point B,2 m

I

B

=

4π(2)

2

P

I

B

=

16π

64π×10

−11

10 m

−2

⇒I

B

=4×10

−11

wm

−2

⇒ Sound level at 2m=10log(

I

I

B )

=10log(10 −12

4×10 −11)

=10log40

=16.02

Hence Sound level at 2m from sourceis 16 dB

5 0
3 years ago
Global warming will produce rising sea levels partly due to melting ice caps but also due to the expansion of water as average o
ludmilkaskok [199]

Answer:

69×10⁻³ m

Explanation:

The linear thermal expansion coefficient for water is α = 69×10⁻⁶ K⁻¹.

Thermal expansion equation:

α ΔT = ΔL / L

Given ΔT = 1.00ºC = 1.00 K and L = 1.00 km = 1.00×10³ m:

(69×10⁻⁶ K⁻¹) (1.00 K) = ΔL / (1.00×10³ m)

ΔL = 0.069 m

ΔL = 69×10⁻³ m

7 0
3 years ago
A cat walks along a plank with mass M= 6.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a di
dimulka [17.4K]

Answer:

d₂ = 1.466 m

Explanation:

In this case we must use the rotational equilibrium equations

        Στ = 0

        τ = F r

we must set a reference system, we use with origin at the easel B and an axis parallel to the plank , we will use that the counterclockwise ratio is positive

      + W d₁ - w_cat d₂ = 0

      d₂ = W / w d₁

      d₂ = M /m d₁

      d₂ = 5.00 /2.9    0.850

      d₂ = 1.466 m

6 0
3 years ago
A concave spherical mirror has a radius of curvature of magnitude 20.0 cm. (a) Find the location of the image for object distanc
Tems11 [23]

Answer:

Answered

Explanation:

The radius of curvature of the mirror R = 20 cm

then the focal length f = R/2 = 10 cm

(a) From mirror formula

 1/f = 1/di + /1do

then the image distance

    di = fd_o / d_o - f

  = (10)(40) / 40-10

 = 30.76 cm

since the image distance is positive so the image is real

ii) when the object distance d_0=20 cm

 di = 10×20/ 20-10

= 20

Hence, the image must be  real

iii)when the object distance d_0 = 10

di = 10×10 / 10-10 =  ∞ (infinite)

the image will be formed at ∞

here also image will be real but diminished.

7 0
3 years ago
Read 2 more answers
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