The work done by the three students is 3,000 J.
The energy transferred in the process is 3,000 J.
<h3>What is work done?</h3>
- Work done is the product of force and distance moved by the object.
W = Fd
The work done by the three students is calculated as follows;
W = 300 x 10
W = 3,000 J
<h3>What is energy transfer?</h3>
- This is means by which energy is converted from one form to another.
The energy transferred in the process is determined by work energy theorem.
E = W
E = 3,000 J
Learn more about work-energy theorem here: brainly.com/question/22236101
Answer:
Explanation:
Given that,
A point charge is placed between two charges
Q1 = 4 μC
Q2 = -1 μC
Distance between the two charges is 1m
We want to find the point when the electric field will be zero.
Electric field can be calculated using
E = kQ/r²
Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.
Then, the magnitude of the electric at point x is zero.
E = kQ1 / r² + kQ2 / r²
0 = kQ1 / x² - kQ2 / (1-x)²
kQ1 / x² = kQ2 / (1-x)²
Divide through by k
Q1 / x² = Q2 / (1-x)²
4μ / x² = 1μ / (1 - x)²
Divide through by μ
4 / x² = 1 / (1-x)²
Cross multiply
4(1-x)² = x²
4(1-2x+x²) = x²
4 - 8x + 4x² = x²
4x² - 8x + 4 - x² = 0
3x² - 8x + 4 = 0
Check attachment for solution of quadratic equation
We found that,
x = 2m or x = ⅔m
So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.
I have no idea what that is, but all of your answers right
Explanation:
CON EL TEOREMA DE PITÁGORAS
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= 27.7 km/h