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Basile [38]
3 years ago
5

How can Newton's third law describe the forces affecting a rocket as it

Physics
2 answers:
Vitek1552 [10]3 years ago
6 0

Answer: the answer is C

Explanation: I just took the test

Alexxandr [17]3 years ago
6 0

Answer:

C

Explanation:

The force the rocket exerts on the air is in the direction opposite to

the force that the air exerts on the rocket.

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A car of weight 300N moved through a distance of 10m when pushed by 3 students
Sati [7]

The work done by the three students is 3,000 J.

The energy transferred in the process is 3,000 J.

<h3>What is work done?</h3>
  • Work done is the product of force and distance moved by the object.

W = Fd

The work done by the three students is calculated as follows;

W = 300 x 10

W = 3,000 J

<h3>What is energy transfer?</h3>
  • This is means by which energy is converted from one form to another.

The energy transferred in the process is determined by work energy theorem.

E = W

E = 3,000 J

Learn more about work-energy theorem here: brainly.com/question/22236101

3 0
2 years ago
A point charge A of charge +4micro coloumb and another B of -1 micro coloumb are placed at a distance in air 1m apart then the d
andrew11 [14]

Answer:

Explanation:

Given that,

A point charge is placed between two charges

Q1 = 4 μC

Q2 = -1 μC

Distance between the two charges is 1m

We want to find the point when the electric field will be zero.

Electric field can be calculated using

E = kQ/r²

Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.

Then, the magnitude of the electric at point x is zero.

E = kQ1 / r² + kQ2 / r²

0 = kQ1 / x²  - kQ2 / (1-x)²

kQ1 / x² = kQ2 / (1-x)²

Divide through by k

Q1 / x² = Q2 / (1-x)²

4μ / x² = 1μ / (1 - x)²

Divide through by μ

4 / x² = 1 / (1-x)²

Cross multiply

4(1-x)² = x²

4(1-2x+x²) = x²

4 - 8x + 4x² = x²

4x² - 8x + 4 - x² = 0

3x² - 8x + 4 = 0

Check attachment for solution of quadratic equation

We found that,

x = 2m or x = ⅔m

So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.

5 0
3 years ago
What I the Wannnsjsusbevdyx
Arada [10]
I have no idea what that is, but all of your answers right
3 0
3 years ago
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A motor boat is headed at a velocity of 25 kilometers/hour toward the north, while the velocity of the water current is 12 kilom
Tems11 [23]

Explanation:

CON EL TEOREMA DE PITÁGORAS

<em>v</em> = \sqrt{(12 km/h)^{2} + (25 km/h)^{2}} = 27.7 km/h

8 0
3 years ago
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. how high does it rise (v = 0 cm
Aliun [14]
Do you need more info?

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