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Basile [38]
4 years ago
5

How can Newton's third law describe the forces affecting a rocket as it

Physics
2 answers:
Vitek1552 [10]4 years ago
6 0

Answer: the answer is C

Explanation: I just took the test

Alexxandr [17]4 years ago
6 0

Answer:

C

Explanation:

The force the rocket exerts on the air is in the direction opposite to

the force that the air exerts on the rocket.

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According to the law of universal gravitation, gravity is the force keeping objects in the universe in their relative positions.
Nat2105 [25]

Answer true

Explanation

3 0
3 years ago
Write the equation for eccentricity
Svetradugi [14.3K]
<span>e=ca{\displaystyle e={\frac {c}{a}}}.</span>

3 0
3 years ago
Water runs into a fountain, filling all the pipes, at a steady rate of 0.750 m3&gt;s. (a) How fast will it shoot out of a hole 4
kati45 [8]

Answer:

velocity  = 472 m/s

velocity = 52.4 m/s

Explanation:

given data

steady rate = 0.750 m³/s

diameter = 4.50 cm

solution

we use here flow rate formula that is

flow rate = Area × velocity .............1

0.750 = \frac{\pi }{4} × (4.50×10^{-2})²  × velocity

solve it we get

velocity  = 472 m/s

and

when it 3 time diameter

put valuer in equation 1

0.750 = \frac{\pi }{4} × 3 ×  (4.50×10^{-2})²  × velocity

velocity = 52.4 m/s

5 0
3 years ago
Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble
Neporo4naja [7]

Answer:

2.4 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v

0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v

0.12 kg m/s = (0.05 kg) v

v = 2.4 m/s

4 0
3 years ago
A toy car of mass 0.15kg accelerates from a speed of 10 cm/s to a speed of 15 cm/s. What is the impulse acting on the car?
OLga [1]

v=v2-v1=15-10=5 cm/s

p=mv=0.15•5=0.75 kg•cm/s

7 0
3 years ago
Read 2 more answers
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