Three carts of masses 4.0 kg, 10kg, and 3.0 kg move on a frictionless track with speeds of v1 = 5.0m/s, v2=3.0m/s, and v3=-3.6 m
1 answer:
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Answer:
Explanation:
distance between two slit d =
d = 18.15 x 10⁻⁷ m
Let wave length of light λ
formula for position of first pair of bright spot
Tanθ = λ / d , λ is wave length of light and d is distance between two slit .
Tan 15.4 =
λ = Tan 15.4 x 18.15 x 10⁻⁷
=5 x 10⁻⁷ m
If θ be the position of next bright spot
Tanθ = 2 λ / d
=
=
θ = 28.4 degree .
Answer:
The tension in the rope is 20 N
Solution:
As per the question:
Mass of the object, M = 2 kg
Density of water,
Density of the object,
Acceleration due to gravity, g =
Now,
From the fig.1:
'N' represents the Bouyant force and T represents tension in the rope.
Suppose, the volume of the block be V:
V = (1)
Also, we know that Bouyant force is given by:
Using eqn (1):
From the fig.1:
N = Mg + T
40 = 2(10) + T
T = 40 - 20 = 20 N
