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lesya692 [45]
1 year ago
5

Explain and briefly summarize the egg example that Czerski uses to explain the law of conservation of angular momentum. Then, co

me up with a forensics-based example that would explain this law or a forensic scenario where this law could come into play and be discussed.
Biology
1 answer:
Oliga [24]1 year ago
6 0

The egg example that Czerski uses to explain the law of conservation of angular momentum is that according to the principle of conservation of angular momentum, anything that is spinning will keep spinning until it is stopped.

Similarly, in the example of an egg given by Czerski If you spin a raw egg and then try to stop it by placing your finger on the shell, the egg will continue to spin since the uncooked portion of it is still in motion.

The law of conservation of angular momentum states that an object's angular momentum won't change in the absence of any external tension.

Its angular momentum is conserved as long as there is no net external torque acting on the system.

In forensic science, reconstruction of crime scenes is a crucial application of physics because instances involving accidents, body falls from heights, weapon projectile motion, bullet or tool case analysis, glass penetration of quick stone.

And law of conservation of angular momentum plays a great role in the reconstruction of those crime scenes and also in the firearm identification.

Learn more about law of conservation of angular momentum here brainly.com/question/7538238

#SPJ1

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- 100 grams of food A (x)

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According to this question, the group of laboratory rats are being fed a daily diet of:

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Let x represent the number of grams needed for food A.

Let y represent the number of grams needed for food B.

This means that:

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Food B: Niacin = 0.66y, Retinol = 40y

Since there are 125.6 units of niacin fed to the rats in total, then;

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Since there are 5400 units of retinol fed to the rats in total, then;

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Solving these two equations simultaneously using elimination method:

0.86x (A) + 0.66y (B) = 125.6 ........(eqn 1)

30x (A) + 40y (B) = 5400 ............ (eqn 2)

Multiply eqn 1 by 30 and eqn 2 by 0.86

30 × 0.86x + 0.66y = 125.6

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25.8x + 34.4y = 4644 ........... (eqn 4)

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y = 876/14.6

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30x + 40(60) = 5400

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30x = 5400 - 2400

30x = 3000

x = 3000/30

x = 100

Therefore, she feeds the group of rats 100grams of food A (x) and 60 grams of food B (y).

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