Answer:
6960 J/kg°C
Explanation:
specific heat= mass×specific heat capacity×increase in temperature
specific heat= 0.240×1450×20= 6960 J/kg°C
hope it helps!
The experimental absolute zero value is less when compared to the accepted value of absolute zero.
<h3>What is absolute zero?</h3>
Absolute zero is defined as the temperature in which the lowest energy possible is attained in a thermodynamic system.
Absolute zero temperature has an accepted values of 0 Kelvin or -273.15 degrees Celsius.
At absolute zero, it is assumed that the volume of an ideal gas becomes zero. However, it has not been possible to cool any gas to absolute zero.
Based on the graph of temperature against volume of gases, the experimental absolute zero extrapolated from the graph where volume of the gases becomes zero is -285 degrees Celsius.
Therefore, the experimental absolute zero value is less when compared to the accepted value.
Learn more about absolute zero at: brainly.com/question/1191114
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The closer to the top the metal is in the list, the more active the metal is and the stronger a reducing agent the metal is. When two different metals are involved in a redox reaction, the metal higher in the list will be oxidized and give up electrons that will reduce the cation of the less active metal.
Majority can such as hydrogen H and oxygen O forming water H2O but uranium having extra neutrons to form plutonium and beyond simply can't because it will not last for a fraction of a second or spiral out of control and violently react like the little boy and the fat man (a uranium and plutonium nuclear weapon) so yes and no
Answer:- HBr is limiting reactant.
Solution:- The given balanced equation is:
From this equation, There is 2:6 mol or 1:3 mol ratio between Al and HBr. Since we have 8 moles of each, HBr is the limiting reactant as we need 3 moles of HBr for each mol of Al.
The calculations could be shown as:
= 24 mol HBr
From calculations, 24 moles of HBr are required to react completely with 8 moles of Al but only 8 moles of it are available. It clearly indicates, HBr is limiting reactant.
