Answer:
that results in an alcohol and a carboxylic acid.
Explanation:
Saponification is a chemical reaction process of alkaline hydrolysis of esters(R'COOR group) by which soap is obtained.
For Example, when a base such as sodium hydroxide [NaOH] is used to hydrolyze an ester, the products are a carboxylate salt and an alcohol. Because soaps are prepared by the alkaline hydrolysis of fats and oils.
In a saponification reaction, alkaline hydrolysis of fats and oils with sodium hydroxide yields propane-1,2,3-triol and the corresponding sodium salts of the component fatty acids.
i.e Fat or oil + caustic alkali ⇒ Soap + propane-1,2,3-triol
As a specific example, ethyl acetate and NaOH react to form sodium acetate and ethanol:
The reaction goes to completion in the image below:
Answer:
At equilibrium, the concentration of 
is going to be 0.30M
Explanation:
We first need the reaction.
With the information given we can assume that is:
+ 
⇄ 2
If there is placed 0.600 moles of NO in a 1.0-L vessel, we have a initial concentration of 0.60 M NO; and no nor present. Immediately, and are going to be produced until equilibrium is reached.
By the ICE (initial, change, equilibrium) analysis:
I: []=0 ; [ ]= 0 ; []=0.60M
C: []=+x ; [ ]= +x ; []=-2x
E: []=0+x ; [ ]= 0+x ; []=0.60-2x
Now we can use the constant information:
![K_{c}=\frac{[products]^{stoichiometric coefficient} }{[reactants]^{stoichiometric coefficient} }](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5Bproducts%5D%5E%7Bstoichiometric%20coefficient%7D%20%7D%7B%5Breactants%5D%5E%7Bstoichiometric%20coefficient%7D%20%7D)
= 
= 
= 
At equilibrium, the concentration of is going to be 0.30M
It is usually neutral becase its is close to neutral number 7
The answer would be: <span>dependent on the number of particles
If you see the ideal gas formula you know that volume is directly related to the number of particles.
Closed container volume could influence the pressure that will change the volume but the question seems to talk about open container. If the container is not closed, then the volume of container won't have any effect.
Mass is related to the number of particles, but not directly related to volume so this option is a bit ambiguous.</span>
