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xz_007 [3.2K]
3 years ago
13

The expression 2Ag + SAg2S is called a(n)

Chemistry
1 answer:
Ber [7]3 years ago
4 0
I guess it is called an Equation !!
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Percentage of isotopes in 35/17 Cl and 37/17 Cl with the molar mass of chlorine as 35.5g and the mass of each nucleon to be 1.00
AlekseyPX

Answer:

The abundance of 35/17 Cl is 75% and 25% of 37/17Cl

Explanation:

The molar mass of an atom is defined as the sum of the masses of each isotope times its abundance, that is:

35.5amu = 35amu*X + 37amu*Y <em>(1)</em>

<em>Where X is the abundance of the 35/17Cl and Y the abundance of 37/17 Cl</em>

<em />

As there are just these 2 isotopes and the abundances of both isotopes = 1:

X + Y = 1 <em>(2)</em>

<em></em>

Replacing (2) in (1):

35.5 = 35X + 37(1-X)

35.5 = 35X + 37 - 37X

-1.5 = -2X

X = 0.75 = 75%

And Y = 100-75% = 25%

<h3>The abundance of 35/17 Cl is 75% and 25% of 37/17Cl</h3>
4 0
3 years ago
When 4.979 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 16.20 grams of CO2 and 4.976 grams of H
dimaraw [331]
For Hydrocarbon combustion:

CₓHₐ + O₂ → xCO₂ + a/2 H₂O

Moles of CO₂ = 16.2 / 44 = 0.37
Moles of Carbon = 0.37
Moles of H₂O = 4.976 / 18 = 0.28
Moles of Hydrogen = 0.28 x 2 = 0.56

Molar ratio = C : H = 1 : 1.5
= 2 : 3
C₂H₃

Mass of empirical unit = 12 x 2 + 1 x 3
= 27
Mr = 54.09
Number of empirical units repeated: 54.09 / 27
= 2

Molecular formula = C₄H₆
5 0
3 years ago
Acetylene, C2H2, burns according to the following reaction: C2H2 5O2 --&gt; 4CO2 2H2O. Suppose 1.20 g of C2H2 is mixed with 3.50
OLEGan [10]
WWWWWWAAAAAAPPPPPP!!!!!
8 0
3 years ago
Which of the following is not an example of a molecule?
satela [25.4K]

Mn is the answer i just took the test

6 0
3 years ago
Read 2 more answers
Write the formulas for the following ionic compounds: (a) copper bromide (containing the Cu+ ion), (b) manganese oxide (containi
ivann1987 [24]

Answer:The formulas of ionic compounds are:

a)CuBr

b)Mn_2O_3

c)Hg_2I_2

d)Mg_3(PO_4)_2

Explanation:

Formulas for the an ionic compounds is determine by:

Criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

(a) Copper bromide :Given that it contains Cu^+ ion.

Cu^++Br^-\rightarrow CuBr

(b) Manganese oxide : Given that it contains Mn^{3+} ion.

Mn^{3+}+O^{2-}\rightarrow Mn_2O_3

(c)Mercury iodide :Given that it contains Hg_2^{2+}

Hg_2^{2+}+I^-\rightarrow Hg_2I_2

(d) Magnesium phosphate :Given that it contains PO_4^{3-}

Mg^{2+}+PO_4^{3-}\rightarrow Mg_3(PO_4)_2

4 0
3 years ago
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