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1 year ago

8

2.2 question 7) Which lines are perpendicular? The_____ lines are perpendicular (blue and green) How do you know? The product of

their slopes is....

1 answer:

Scrat [10]1 year ago

7 0

It’s the expression 2.2 and you add and subtract 3

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The siberian tiger can grow up to 10 5/4 feet long. express this length as a decimal

Komok [63]

The answer is 10.80. Hope this helps :)

6 0

3 years ago

The net of a triangular prism is shown. Use the ruler provided to measure the dimensions of the net to the nearest half centimet

Black_prince [1.1K]

If the area of the triangle and the rectangle is 4 square cm and 2 square cm. Then the total surface area of the triangular prism will be 14 square cm.

<h3>What is a triangular prism?</h3>

A closed solid with two parallel triangular bases joined by a rectangle surface is known as a triangular prism.

The total surface area of the triangular prism will be

Total surface area = 2(area of the triangle) + 3(area of the rectangle)

The area of the rectangle will be

Rectangle area = 2 x 1

Rectangle area = 2 square cm

The area of the triangle will be

Triangle area = 0.5 x 4 x 2

Triangle area = 4 square cm

Then the total surface area will be

Total surface area = 2 x 4 + 3 x 2

Total surface area = 8 + 6

Total surface area = 14 square cm

More about the triangular prism link is given below.

brainly.com/question/24046619

#SPJ1

5 0

2 years ago

The vector v=(7,1) lies entirely in quadrant 1. Give possible coordinates for the initial point and terminal point of the vector

slamgirl [31]

Answer:

A possible initial point is (1,4) and a possible terminal point is (8,5)

Step-by-step explanation:

The given vector is $\vec{v}=(7,1)$ .

We can rewrite this vector as:

$\vec{v}=\binom{7}{1}$

The x-components is 7 and the y-component is 1.

We can choose initial point (a,b) and terminal point (c,d) in the first quadrant such that $c-a=7$ and $d-b=1$

If a=1, and b= 4, then:

$c-1=7$ and $d-4=1$

This implies that:

$c=7+1=8$ and $d=1+4=5$

Therefore a possible initial point is (1,4) and a possible terminal point is (8,5)

6 0

3 years ago

Please someone with a good heart help me ;-;<br>

jeyben [28]

Answer:

87.5 ft^3

Step-by-step explanation:

Formula:

Volume = length x width x height.

Dimensions:

Length = 3 1/2 ft = 7/2 ft

Width = 5 ft

Height = 2 1/2 ft = 5/2 ft

Substitute and Find Volume:

Volume = (7/2 ft) x (5 ft) x (5/2) ft

Volume = 87.5 ft^3

6 0

2 years ago

Select all the correct answers.<br> In which pairs of matrices does AB = BA?

horsena [70]

In order to multiply a matrix by another matrix, we multiply the rows in the first matrix by the columns in the other matrix (How this is done is shown below)

To determine the pairs of matrices that AB=BA, we will determine AB and BA for each of the options below.

For the first option

$A= \left[\begin{array}{cc}1&0&-2&1&\end{array}\right]; B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\$

$AB= \left[\begin{array}{cc}(1\times5)+(0\times3)&(1\times0)+(0\times 2)&(-2\times5)+(1\times3)&(-2\times0)+(1\times2)&\end{array}\right]\\AB= \left[\begin{array}{cc}5+0&0+0&-10+3&0+2&\end{array}\right]\\AB = \left[\begin{array}{cc}5&0&-7&2&\end{array}\right] \\$

and

$BA= \left[\begin{array}{cc}(5\times1)+(0\times-2)&(5\times0)+(0\times 1)&(3\times1)+(2\times-2)&(3\times0)+(1\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}5+0&0+0&3+-4&0+2&\end{array}\right]\\BA = \left[\begin{array}{cc}5&0&-1&2&\end{array}\right] \\$

∴ AB≠BA

For the second option

$A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]; B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\$

$AB= \left[\begin{array}{cc}(1\times3)+(0\times6)&(1\times0)+(0\times -3)&(-1\times3)+(2\times6)&(-1\times0)+(2\times-3)&\end{array}\right]\\AB= \left[\begin{array}{cc}3+0&0+0&-3+12&0+-6&\end{array}\right]\\AB = \left[\begin{array}{cc}3&0&9&-6&\end{array}\right] \\$

and

$BA= \left[\begin{array}{cc}(3\times1)+(0\times-1)&(3\times0)+(0\times 2)&(6\times1)+(-3\times-1)&(6\times0)+(-3\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}3+0&0+0&6+3&0+-6&\end{array}\right]\\BA = \left[\begin{array}{cc}3&0&9&-6&\end{array}\right] \\$

Here AB = BA

For the third option

$A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]; B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\$

$AB= \left[\begin{array}{cc}(1\times5)+(0\times3)&(1\times0)+(0\times 2)&(-1\times5)+(2\times3)&(-1\times0)+(2\times2)&\end{array}\right]\\AB= \left[\begin{array}{cc}5+0&0+0&-5+6&0+4&\end{array}\right]\\AB = \left[\begin{array}{cc}5&0&1&4&\end{array}\right] \\$

and

$BA= \left[\begin{array}{cc}(5\times1)+(0\times-1)&(5\times0)+(0\times 2)&(3\times1)+(2\times-1)&(3\times0)+(2\times2)&\end{array}\right]\\BA= \left[\begin{array}{cc}5+0&0+0&3+-2&0+4&\end{array}\right]\\BA = \left[\begin{array}{cc}5&0&1&4&\end{array}\right] \\$

Here also, AB=BA

For the fourth option

$A= \left[\begin{array}{cc}1&0&-2&1&\end{array}\right]; B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\$

$AB= \left[\begin{array}{cc}(1\times3)+(0\times6)&(1\times0)+(0\times -3)&(-2\times3)+(1\times6)&(-2\times0)+(1\times-3)&\end{array}\right]\\AB= \left[\begin{array}{cc}3+0&0+0&-6+6&0+-3&\end{array}\right]\\AB = \left[\begin{array}{cc}3&0&0&-3&\end{array}\right] \\$

and

$BA= \left[\begin{array}{cc}(3\times1)+(0\times-2)&(3\times0)+(0\times 1)&(6\times1)+(-3\times-2)&(6\times0)+(-3\times1)&\end{array}\right]\\BA= \left[\begin{array}{cc}3+0&0+0&6+6&0+-3&\end{array}\right]\\BA = \left[\begin{array}{cc}3&0&12&-3&\end{array}\right] \\$

Here, AB≠BA

Hence, it is only in the second and third options that AB = BA

$A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right] B= \left[\begin{array}{cc}3&0&6&-3&\end{array}\right] \\$ and $A= \left[\begin{array}{cc}1&0&-1&2&\end{array}\right]B= \left[\begin{array}{cc}5&0&3&2&\end{array}\right] \\$

Learn more on matrices multiplication here: brainly.com/question/12755004

8 0

3 years ago

Read 2 more answers