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Elza [17]
3 years ago
15

I am genuinely so confused please help

Mathematics
1 answer:
Elanso [62]3 years ago
8 0

Answer:

I hope it will help you :)

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5x-25=50 <br> 3x+9=90 n<br> solve both equations
timama [110]

Answer:

1st is x=15

2nd is x=27

Step-by-step explanation:

8 0
3 years ago
What number is added to 0.043 to obtain 6.054?
stich3 [128]
That number is 6.011.
8 0
4 years ago
How to multiply 70.94 by 3.2 and get 227.008
kogti [31]

Answer:

solution

Step-by-step explanation:

so the solution is this first multiply the numbers with out the decimal point and then count and add the decimal point.

7 0
3 years ago
Read 2 more answers
The function h(t) = -16t^2 + 16t represents the height (in feet) of a horse (t) seconds after it jumps during a steeplechase.
Vladimir79 [104]
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.

h'(t) = -32t + 16

When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.

-32t + 16 = 0

-32t = -16

t = 0.5 seconds

b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.

h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet

If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.

c.) We know that the horse is in the air whenever h(t) is greater than 0. 

-16t^2 + 16t = 0

-16t(t-1)=0

t = 0 and 1

So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
7 0
3 years ago
The length of a rectangle is increasing at a rate of 9 cm/s and its width is increasing at a rate of 4 cm/s. When the length is
Setler [38]

Answer:

The area of the rectangle is increasing at a rate of 168 square centimeters per second.

Step-by-step explanation:

Geometrically speaking, the area of a rectangle (A), in square centimeters, is described by following expression:

A = w\cdot l (1)

Where:

w - Width, in centimeters.

h - Height, in centimeters.

By Differential Calculus, we find an expression for the rate of change of the area of the rectangle (\dot A), in square centimeters per second:

\dot A = \dot w\cdot l + w\cdot \dot l (2)

Where:

\dot w - Rate of change of the width of the rectangle, in centimeters per second.

\dot l - Rate of change of the length of the rectangle, in centimeters per second.

If we know that w = 12\,cm, l = 15\,cm, \dot w = 4\,\frac{cm}{s} and \dot l = 9\,\frac{cm}{s}, then the rate of change of the area of the rectangle is:

\dot A = \dot w\cdot l + w\cdot \dot l

\dot A = 168\,\frac{cm^{2}}{s}

The area of the rectangle is increasing at a rate of 168 square centimeters per second.

6 0
3 years ago
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