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slavikrds [6]
3 years ago
9

Please help. Will give brainliest!!

Mathematics
1 answer:
Gre4nikov [31]3 years ago
5 0
Done using cramas method
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Question 1 (5 points)
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Answer:

85%

Step-by-step explanation:

If they had a 15% chance out of 100% to win free movie tickets, just subtract the 15% from the 100% to get your answer. Hope it helps.

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3 years ago
5. y/-3= 1/6<br><br> what does y=
jeka94

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With the help of a conservation program, the number of
mart [117]

Answer:

b

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3 years ago
Differentiate Vx(x + 2) with respect to x.
Travka [436]

Answer:

y'= \frac{3x+2}{2\sqrt{x} }

General Formulas and Concepts:

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

y=\sqrt{x} (x+2)

<u>Step 2: Rewrite</u>

y=x^{\frac{1}{2} } (x+2)

<u>Step 3: Differentiate</u>

  1. Product Rule [Basic Power/Chain Rule]:                 y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)
  2. Simplify:                                                                            y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}
  3. Rewrite:                                                                                        y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}
  4. Add:                                                                                                       y'= \frac{3x+2}{2\sqrt{x} }
7 0
3 years ago
The sum of the ages of Ajeet and Ajay is 40 years. After 10 years, Ajeet will be twice as old as Ajay. Find the present ages of
nevsk [136]

Answer:

Check pdf

Step-by-step explanation:

Download pdf
8 0
3 years ago
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