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statuscvo [17]
2 years ago
7

Light with wavelength in air ( lambdaair ) is incident on a oil slick ( noil = 1. 25) floating on the ocean ( nwater = 1. 33). w

hat is the thinnest thickness of oil that will brightly reflect the light?
Physics
1 answer:
crimeas [40]2 years ago
4 0

<u>26mm</u> is the thinnest thickness of oil that will brightly reflect the light.

What is wavelength ?

The distance over which a periodic wave's shape repeats is known as the wavelength in physics.  It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.  The spatial frequency is the reciprocal of wavelength. The Greek letter lambda () is frequently used to represent wavelength. The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.

To learn more about wavelength visit:

brainly.com/question/16051869

#SPJ4

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A 75 kg bobsled is pushed along a horizontal surface by two athletes. After the bobsled is pushed a distance of 4.5m starting fr
sergejj [24]

Answer:

The net force acting on the bobsled is 300 N.

Explanation:

Given:

Mass of the bobsled is, m=75\ kg

Displacement is, d=4.5\ m

Initial speed is, u=0m/s

Final speed is, v=6.0 m/s

Net acceleration acting on the bobsled can be determined using the following Newton's equation of motion:

v^2=u^2+2ad

Plug in all the given values and solve for acceleration, a.

(6.0)^2=0+2a(4.5)\\36=9a\\a=\frac{36}{9}=4\ m/s^2

Now, as per Newton's second law, net force is the product of mass and acceleration. So,

F_{net}=ma\\F_{net}=75\times 4=300\ N

Therefore, the net force acting on the bobsled is 300 N.

7 0
3 years ago
A cart of mass 6.0 kg moves with a speed of 3.0 m/s towards a second stationary cart with a mass of 3.0 kg. The carts move on a
IgorLugansk [536]

Answer:1.5

Explanation:

Given

mass of first  cart m_1=6 kg

initial Velocity u_1=3 m/s

mass of second cart m_2=3 kg

u_2=0 m/s

In the absence of External Force we can conserve momentum

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{m_1+m_2}

v=\frac{6\times 3+3\times 0}{6+3}

v=2 m/s

Final kinetic Energy of two masses

K.E._2=\frac{1}{2}(m_1+m_2)v^2

K.E._2=\frac{1}{2}\cdot (3+6)\cdot (2)^2

K.E._2=18 J

Initial Kinetic Energy

K.E._1=\frac{1}{2}m_1u_1^2+\frac{1}{2}m_2u_2^2

K.E._1=\frac{1}{2}6\times 3^2+0

K.E._1=27 J

ratio =\frac{K.E._1}{K.E._2}=\frac{27}{18}=1.5

5 0
4 years ago
You are crouched at the "start" line. Bang! The race begins and 7 seconds later you end up 60 yards down the track. What was you
Nutka1998 [239]

Answer:

a = 7.35 ft / s²

Explanation:

For this exercise we must use the kinematics relations

        x = v₀ t + ½ a t²

as the runner leaves the starting line his initial velocity is zero

        x = ½ a t²

        a = \frac{2x}{t^2}

let's reduce the distance to foot

        x = 60 yd (3ft / 1yd) = 180 ft

let's calculate

         a = 2 180 / 7²

         a = 7.35 ft / s²

6 0
3 years ago
How far will a freely falling object fall from rest in five seconds? six seconds?
Vanyuwa [196]
Distance = 1/2*gravity*velocity^2 
<span>So plugging: 1/2 * 9.8 * 25 = 122.5units
 and is six second
</span><span>Distance = 1/2*gravity*velocity^2 
</span><span>So plugging: 1/2 * 9.8 * 36= 176.4 units</span>
4 0
3 years ago
The chain reaction used in nuclear power plants involves a free _______ colliding with a _______ , forming more free neutrons an
sertanlavr [38]
-- Free neutrons collide with Uranium nuclei. 

If one is absorbed, then

-- the Uranium nucleus falls apart,

producing

-- smaller nuclei,
-- energy,

and

-- more free neutrons.
7 0
3 years ago
Read 2 more answers
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