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olya-2409 [2.1K]
3 years ago
10

What type of image results when the object is located between 2f (2 focal lengths) and f (the focal point) of a convex lens?

Physics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

C

Explanation:

the image formed is real but inverted and magnified

you can remember it by R I M

hope this helps

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A 2.0-kilogram mass is located 3.0 meters above
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The correct answer is: Option (3) 9.8 N/kg

Explanation:

According to Newton's Law of Gravitation:

F_g = \frac{GmM}{R^2} --- (1)

Where G = Gravitational constant = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²

m = Mass of the body = 2 kg

M = Mass of the Earth = 5.972 × 10²⁴ kg

R = Distance of the object from the center of the Earth = Radius of the Earth + Object's distance from the surface of the Earth = (6371 * 10³) + 3.0 = 6371003 m

Plug in the values in (1):

(1)=> F_g = \frac{6.67408 * 10^{-11} * 2 * 5.972*10^{24}}{(6371003)^2} = 19.63

Now that we have force strength at the location, we can use:

Force = mass * gravitational-field-strength

Plug in the values:

19.63 = 2.0 * gravitational-field-strength

gravitational-field-strength = 19.63/2 = 9.82 N/kg

Hence the correct answer is Option (3) 9.8 N/kg

4 0
4 years ago
Read 2 more answers
A pendulum consists of a 0.3 kg mass at the end of a string. The pendulum is raised to a height of 0.26 m and released. When the
Debora [2.8K]

The total energy of the Pendulum-Earth system is equal to 1.54416 Joules.

<u>Given the following data:</u>

  • Mass = 0.3 kg
  • Height = 0.26 meter.
  • Velocity = 2.28 m/s.

<u>Scientific data:</u>

  • Acceleration due to gravity on Earth = 9.8 m/s^2

To calculate the total energy of the Pendulum-Earth system:

<h3>How to calculate total energy.</h3>

The total energy possessed by this Pendulum-Earth system is equal to the sum of both the potential energy and kinetic energy at its lowest point.

Mathematically, the total energy is given by this formula:

E = mgh + \frac{1}{2} mv^2

Substituting the given parameters into the formula, we have;

E = 0.3 \times 9.8 \times 0.26 + \frac{1}{2}\times 0.3 \times 2.28^2\\\\E=0.7644+0.77976

E = 1.54416 Joules.

Read more on kinetic energy here: brainly.com/question/17081653

6 0
2 years ago
How do stars serve as evidence for the expansion of the universe and the Big Bang theory?​
castortr0y [4]

Answer:

The Doppler red-shift of light observed from distant stars and galaxies gives evidence that the universe is expanding (moving away from a central point). This allows for Big Bang Theory, because after a “bang” occurs all of the matter moves away from the point of origin.

7 0
4 years ago
Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml
Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of  electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}

Put the value into the formula

E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}

E=2.41\times10^{3}\ V/m

Hence, The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

3 0
4 years ago
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